Square root of 40 in decimal form I’m terrible at decimals :/
2 answers:
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Answer: 120
Step-by-step explanation:
The total number of digits from 1 to 9 = 10
The number of digits from less than 5 (0,1,2,3,4)=5
Since repetition is not allowed so we use Permutations , then the number of 3-digit different codes will be formed :-
The number of digits from greater than 4 (5,6,7,8,9)=5
Similarly, Number of 3-digit different codes will be formed :-
Hence, the required number of 3-digit different codes = 60+60=120
First bag has 47 coins and second bag has 49 coins and third bag has 51 coins and fourth bag has 53 coins
<em><u>Solution:</u></em>
Given that,
Total number of coins = 200
Number of bags = 4
<em><u>I put the coins into each bag so that each bag has 2 more coins than the one before</u></em>
Therefore,
Each bag has 2 more coins than the one before. Based on this we can say,
Let "x" be the number of coins put in first bag
Then, x + 2 is the number of coins put in second bag
Then, x + 4 is the number of coins put in third bag
Then, x + 6 is the number of coins put in fourth bag
We know that,
Total number of coins = 200
Thus,
Coins put in first bag = x = 47
Coins put in second bag = x + 2 = 47 + 2 = 49
Coins put in third bag = x + 4 = 47 + 4 = 51
Coins put in fourth bag = x + 6 = 47 + 6 = 53
Thus number of coins in each bag are found
Answer:
The remainder is zero
Step-by-step explanation:
To find the remainder we will use the long division
⇒(1)
⇒(2)
⇒(3)
From (1) , (2) and (3)
The quotient of the long division is and no remainder
So the remainder is zero
* If you want to check your answer Multiply the quotient by the divisor