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Vlad1618 [11]
4 years ago
6

How do you write 4.25 as a mixed number?

Mathematics
1 answer:
otez555 [7]4 years ago
8 0
————4 1/4. Or 17/4————
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5. Shara's new lawn sprinkler watered a circular area with three times the radius of the old sprinkler. How many times greater w
Art [367]
The answer is C. when you have questions like these, its best to plug in an easy number and test it out. 

Say the original radius was 2. That means the area of that sprinkler was 12.56 (if you use the formula Pi(radius)squared. 

a number 3 times bigger then 2, is 6. (2 times 3 = 6) There fore, following the same formula as before, you plug that number in and get 113.04 as the area of the new sprinkler. 

113.04 divided by 12.56 is 9
6 0
3 years ago
Maureen proposes given each student two free tickets, with the price represented
Masja [62]

Answer:

2x + 1

12x

Step-by-step explanation:

7 0
3 years ago
Jim Lee received his bank statement from Bayne Bank indicating a balance of $7,980. Lee's checkbook showed a balance of $6,800.
bezimeni [28]
<span>Given:
Bayne Bank indicating a balance of $7,980.
Lee's checkbook showed a balance of $6,800.
checks outstanding were $1,330.
NSF check for $120 and a service charge of $30. 

Bank balance:                     7,980
less: outstanding checks <u>   (1,330)</u>
Bank balance, end              6,650

Jim's checkbook balance:   6,800
less: NSF check      120
         service charge 30    <u>   (150)</u>
Jim's balance, end              6,650

The reconciled balance is: $6,650.

In reconciling the bank balance, we need to add the deposits in transit and deduct the outstanding checks. This are all transactions reflected in the book but not yet reflected in the bank account.

In reconciling the book balance, we need to add the credits made in the bank account and deduct the debits like service charges.</span>
5 0
3 years ago
Given: ABCD ∥gram, BK ⊥ AD , AB ⊥ BD AB=6, AK=3 Find: m∠A, BK, Area of ABCD
Morgarella [4.7K]

1. Consider right triangle ABK. In this triangle AB is the hypotenuse, BK and AK are legs. By the Pythagorean theorem,

AB^2=AK^2+BK^2,\\\\6^2=3^2+BK^2,\\\\BK^2=36-9=27,\\\\BK=3\sqrt{3}\ un.

2. Use the definition of \cos \angle A:

\cos \angle A=\dfrac{\text{adjacent leg}}{\text{hypotenuse}}=\dfrac{AK}{AB}=\dfrac{3}{6}=\dfrac{1}{2}.

Then m\angle A=60^{\circ}.

3. Consider right triangle ABD. In this triangle AD is the hypotenuse, AB and BD are legs. Since  m\angle A=60^{\circ}, then

m\angle BDA=180^{\circ}-90^{\circ}-60^{\circ}=30^{\circ}.

The leg that is opposite to the angle of 30° is half of the hypotenuse, so

AD=2AB=12\ un.

4. The area of parallelogram aBCD is

A_{ABCD}=AD\cdot BK=12\cdot 3\sqrt{3}=36\sqrt{3}\ sq. un.

3 0
3 years ago
Hello! :)
bazaltina [42]

Answer:

8x-2y

Step-by-step explanation:

3x4y+5x+2y

Simplify

1 Combine like terms

3x4y+5x+2y

8x-4y+2y

2 Combine like terms

8x-4y+2y

8x-2y

Solution

8x-2y

Hope this helps!

Don't forget to mark me as Brainliest.

4 0
2 years ago
Read 2 more answers
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