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CaHeK987 [17]
3 years ago
8

Mrs. Valdez wanted to determine the number of people, p, she could safely take in her car to the fun run. She determined that p

< 5. Which statement best describes a possible number of people she can take in her car?
Mrs. Valdez can take –2 people because –2 < 5.

Mrs. Valdez can take 2 people because 2 < 5.

Mrs. Valdez can take 3.5 people because 3.5 < 5. NOT THIS

Mrs. Valdez can take 5 people because 5 < 5.


its not c


What is the first step in solving the inequality < –1?


Multiply both sides by 6.

Add 2 to both sides. NOT THIS ONE

Change the direction of the inequality.

Change the inequality to ≤.
Mathematics
1 answer:
dolphi86 [110]3 years ago
5 0

Answer:

for the first question b,


it doesn't make sense for choice a to have -2 people in the car. You can't have a negative amount of people. For choice choice c, you can't have half a person, and for choice d, Ms. Valdez can only have under 5 people, not five people exactly.


for the second question I need to see the whole inequality, generally there is a variable, and all i see is <-1, which is invalid.


hope this helps, if it does like it pls!!


Step-by-step explanation:


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For the following linear system, put the augmented coefficient matrix into reduced row-echelon form.
Anni [7]

Answer:

The reduced row-echelon form of the linear system is \left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]

Step-by-step explanation:

We will solve the original system of linear equations by performing a sequence of the following elementary row operations on the augmented matrix:

  1. Interchange two rows
  2. Multiply one row by a nonzero number
  3. Add a multiple of one row to a different row

To find the reduced row-echelon form of this augmented matrix

\left[\begin{array}{cccc}2&3&-1&14\\1&2&1&4\\5&9&2&7\end{array}\right]

You need to follow these steps:

  • Divide row 1 by 2 \left(R_1=\frac{R_1}{2}\right)

\left[\begin{array}{cccc}1&3/2&-1/2&7\\1&2&1&4\\5&9&2&7\end{array}\right]

  • Subtract row 1 from row 2 \left(R_2=R_2-R_1\right)

\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\5&9&2&7\end{array}\right]

  • Subtract row 1 multiplied by 5 from row 3 \left(R_3=R_3-\left(5\right)R_1\right)

\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]

  • Subtract row 2 multiplied by 3 from row 1 \left(R_1=R_1-\left(3\right)R_2\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]

  • Subtract row 2 multiplied by 3 from row 3 \left(R_3=R_3-\left(3\right)R_2\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&0&0&-19\end{array}\right]

  • Multiply row 2 by 2 \left(R_2=\left(2\right)R_2\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&-19\end{array}\right]

  • Divide row 3 by −19 \left(R_3=\frac{R_3}{-19}\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&1\end{array}\right]

  • Subtract row 3 multiplied by 16 from row 1 \left(R_1=R_1-\left(16\right)R_3\right)

\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&-6\\0&0&0&1\end{array}\right]

  • Add row 3 multiplied by 6 to row 2 \left(R_2=R_2+\left(6\right)R_3\right)

\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]

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100.7 x 0.009 (basic math im in 5th grade)
pogonyaev

Answer

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Step-by-step explanation:

(100.7)*(0.009)

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What is the value of 4³÷ 2³ ?
Sunny_sXe [5.5K]

Answer:

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Step-by-step explanation:

4^3\div 2^3= \\\\(2^2)^3\div 2^3= \\\\2^{2\cdot 3}\div 2^3= \\\\2^6\div 2^3=\\\\2^{6-3}=\\\\2^3=\\\\8

Hope this helps!

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