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Sav [38]
4 years ago
8

Solve for a if the line through the two given points has the given slope.(a,5) and (1,−5),m=−2

Mathematics
1 answer:
Luba_88 [7]4 years ago
8 0

slope (m) = (y₂ - y₁)/(x₂ - x₁)

-2/1 = (a - 1)/(5 -(-5))

-2 = (a - 1)/10

-20 = a - 1

-19 = a

Answer: a = -19

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(image) The figure below is an isosceles triangle surmounted by a semi-circle. Find the area of the entire region.
S_A_V [24]

Answer:

12.53

Step-by-step explanation:

∠BCA = (180°-40°)/2 = 70°

Laws of Sines: CA/sin 40° = AB/sin 70° = 5/sin 70°

CA = 5/sin 70° * sin 40° = 3.40

area of semicircle CA = (3.1416 * 1.70²) / 2 = 4.54

By Heron's Formula, area of triangle ABC:

1/4 √(a+b+c) (a+b-c) (b+c-a) (c+a-b) = 1/4 * √13.4*3.4*3.4*6.6

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5 0
2 years ago
This is a little hard i guess so i added a little more points :D math btw
Sonbull [250]

Answer:

First,I will add all the numbers up which is 4+5+6+9=24.Then,i would find the total amount of people which is 4.Then you divide it by 4 and you get 6.And there is your answer.Each person get 6 marble.

Step-by-step explanation:

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Solve for x and why please using these!!!
krok68 [10]

Answer:

x = 40

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Step-by-step explanation:

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Edit: Solve for Y

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4 0
3 years ago
3 plus 27 divided by (4 plus 5) Find the sum 1/3 plus 2/5
dezoksy [38]

Answer:

4.) 6

5.) \frac{11}{15}  

Step-by-step explanation:

4.

PEMDAS

Parenthesis, Exponents, Multiplication, Division, Adition, Subtraction.

3 + 27 ÷ ( 4 + 5 )

Do the parenthesis first ( 4 + 5 )

3 + 27 ÷ 9

Do the division next ( 27 ÷ 9)

3 + 3

Now addition.....( 3 + 3)

6

__________________________________________________________

5.

\frac{1}{3} + \frac{2}{5}

In order to find the sum between these 2 fractions, we need to find a common denominator, and in this case, it can be 15...

\frac{1 * 5}{3 * 5} = \frac{5}{15}

\frac{2 * 3}{5 * 3} = \frac{6}{15}

Now that we have a common denominator, we can add them up...

\frac{5}{15} + \frac{6}{15} =\frac{11}{15} \\\\\frac{11}{15}

\frac{11}{15}  is ur answer.

Hope this helped!

Have a supercalifragilisticexpialidocious day!

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