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-BARSIC- [3]
3 years ago
11

PLEASE HELP ME OUT!!

Mathematics
1 answer:
lara31 [8.8K]3 years ago
7 0
The south side of town would be the better option.
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Find f(-7) if f(x) = 2x + 8.
Rom4ik [11]

f(x) = 2x + 8

f(-7) = 2(-7) + 8

f(x) = -14 + 8

f(x) = -6

5 0
3 years ago
Read 2 more answers
Total consumption of fruit juice in a particular country in 2006 was about 1.85 billion gallons. The population of that country
Eduardwww [97]

Given :

Population of country in 2006 , P = 300 million.

Consumption of fruit juice in 2006 by while population, C = 1.85 billion.

To Find :

The average number of gallons of fruit juice consumed per person in the country in​ 2006.

Solution :

We know, 1 billion = 1000 million.

C = 1.85 billion = 1850 million.

Now, average umber of gallons of fruit juice consumed per person in the country in​ 2006 is :

c =\dfrac{C}{P}\\\\c=\dfrac{1850}{300}\ gallons/person\\\\c=6.17 \ gallons/person

Hence, this is the required solution.

4 0
3 years ago
a person walks 80 feet in 40 seconds. what equation represents this relationship. how many feet will the person walk in 10 secon
larisa [96]

Answer:

20 feet

Step-by-step explanation:

\frac{80 feet}{40 seconds}  = \frac{x feet}{10 seconds}

Simplify \frac{80}{40}

\frac{80}{40} = \frac{2}{1}

Every 1 second, a person will walk 2 feet.

\frac{x}{10} = \frac{20}{10}

X = 20 feet

6 0
3 years ago
Read 2 more answers
Compute the correlation coefficient for the data set. (2,19), (3,22), (4,26), (5,20), (6,35), (7,30), (9,40), (10,42), (11,35)
lakkis [162]

Answer:

The correlation coefficient  of the data is 0.8679.

Step-by-step explanation:

The formula to compute the correlation coefficient is:

r(X,Y)=\frac{n\cdot \sum XY-\sum X\cdot \sum Y}{\sqrt{n\cdot\sum X^{2}-(\sum X)^{2}}\times \sqrt{n\cdot\sum Y^{2}-(\sum Y)^{2}}}

From the data provided compute the values of ∑ XY, ∑ X, ∑ Y, ∑ X² and ∑ Y².

The values are computed in the table below.

Compute the correlation coefficient as follows:

r(X,Y)=\frac{n\cdot \sum XY-\sum X\cdot \sum Y}{\sqrt{n\cdot\sum X^{2}-(\sum X)^{2}}\times \sqrt{n\cdot\sum Y^{2}-(\sum Y)^{2}}}

            =\frac{(9\times 1893)-(57\times 269)}{\sqrt{(9\times 441)-(57)^{2}}\times \sqrt{(9\times 8635)-(269)^{2}}}\\\\=\frac{1704}{\sqrt{720\times 5354}}\\\\=0.86788895\\\\\approx 0.8679

Thus, the correlation coefficient  of the data is 0.8679.

4 0
3 years ago
Which is a unit rate?
sineoko [7]

Answer:

20 gallons for 2 hours

Step-by-step explanation:

.........................................

5 0
3 years ago
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