H=+15 m
v=+5 m/s
Ball hits the ground when h(t)=-15m
h(t)=-9.8t^2+vt+h
=>
-15=-9.8t^2+5t+15
9.8t^2-5t-30=0
Solve for t, using quadratic formula,
t=-1.513 or t=2.023
reject negative root due to context, so
t=2.023 seconds
2)
h(t)=-16t^2+20t+8
a. height before pitch is when t=0, or h(0)=8
b. highest point reached when h'(t)=-32t+20=0 => t=5/8 seconds
c. highest point is t(5/8)=-16(5/8)^2+20(5/8)+8=47/5=9.4 m
d. ball hits ground when h(t)=0 => solve t for h(t)=0
=> t=-0.3187 seconds or t=1.569 seconds.
Reject negative root to give
time to hit ground = 1.569 since ball was pitched.
Answer:
Step-by-step explanation:
<u>Volume:</u>
<u>Given r = 5 cm and V = 110 cm³, find h:</u>
- 1100 = π(5²)h
- 1100/25 = πh
- 44 = πh
<u>Curved surface area:</u>
- S = 2πrh = 2*5*πh = 10*44 = 440 cm²
Correct choice is C
9514 1404 393
Answer:
no solution
Step-by-step explanation:
The equations are inconsistent. The set of equations reduces to ...
x + 2y + 3z = 12
x + 2y + 3z = 30
x + 2y + 3z = 60
No values of x, y, and z can satisfy all three equations. There is no solution.
