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ArbitrLikvidat [17]
4 years ago
13

What fraction is between 4/8 and 1

Mathematics
2 answers:
Angelina_Jolie [31]4 years ago
7 0
Answer= 5/8, 6/8, and 7/8
 
There are many fractions between 4/8 and 1.

For the explanation, lets remember that 1, is equivalent to 8/8. 

Comparing 4/8 and 8/8 makes answering the question easier. Since we know the fractions 5/8, 6/8 and 7/8 are between 4/8 and 1(8/8)

So three possible answers could be 5/8, 6/8, and 7/8.
aliina [53]4 years ago
5 0
There are many:

5/8
10/16
20/32
6/8
3/4
12/16
24/32
7/8
14/16
28/32
2/3

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For what value of x does (x + 3)^2-5=0
ArbitrLikvidat [17]

Answer:

x = -3±sqrt( 5)

Step-by-step explanation:

(x + 3)^2-5=0

Add 5 to each side

(x + 3)^2-5+5=0+5

(x + 3)^2 = 5

Take the square root of each side

sqrt((x + 3)^2 )=±sqrt( 5)

x+3 = ±sqrt( 5)

Subtract 3 from each side

x+3-3 = -3±sqrt( 5)

x = -3±sqrt( 5)

7 0
4 years ago
The number 8,046 can be modeled using base ten blocks. How many of each type of block are needed to build the number?
MArishka [77]

Answer:

the first one

Step-by-step explanation:

8 one thousand block is 8000

0 hundreds 000

4 tens. 40

6 ones. 6

8046

7 0
3 years ago
Read 2 more answers
Each plotted plant costs$4.75, each shrub costs$14.50 .
eduard
8 it is this !!!!!!!!!!!!!!!!
8 0
3 years ago
In ΔABC , angle C is a right angle.
guajiro [1.7K]

Answer:  Choice A. sin(A) = cos(B)

============================================================

Explanation:

The rule is that sin(A) = cos(B) if and only if A+B = 90.

Note how

  • sin(A) = opposite/hypotenuse = BC/AB
  • cos(B) = adjacent/hypotenuse = BC/AB

Since both result in the same fraction BC/AB, this helps us see why sin(A) = cos(B). Similarly, we can find that cos(A) = sin(B).

In the diagram below, the angles A and B are complementary, meaning they add to 90 degrees. So this trick only applies to right triangles.

The side lengths can be anything you want, as long as you're dealing with a right triangle.

3 0
3 years ago
Use f(x) = 1/2 x and f -1(x) = 2x to solve the problems. f(2) = 1 f−1(1) = 2 f−1(f(2)) = 2 f−1(−2) = f(−4) = f(f−1(−2)) =
vampirchik [111]

Answer:

In this problem, we are given the following functions:

f(x)=\frac{1}{2}x

and its inverse function:

f^{-1}(x)=2x

First of all, we want to calculate f(2). This can be obtained by substituting

x = 2

into f(x). Doing so, we find:

f(2)=\frac{1}{2}\cdot 2 = 1

Then we want to calculate f^{-1}(1). We can do it by substituting

x = 1

into f^{-1}(x). Doing so,

f^{-1}(1)=2\cdot 1 = 2

Then we want to calculate f^{-1}(f(2)), which can be found by calculating f(2) and then using it as input for f^{-1}(x). We know that

f(2) = 1

Therefore,

f^{-1}(f(2))=f^{-1}(1)=2

Then we want to calculate f^{-1}(-2), which can be calculated by plugging

x = -2

into f^{-1}(x). Doing so,

f^{-1}(-2)=2\cdot (-2)=-4

Then we want to calculate f(-4); by substituting

x = 4

into f(x), we find

f(-4)=\frac{1}{2}\cdot (-4)=-2

Finally, we want to find f(f^{-1}(-2))

We know already that

f^{-1}(-2)=-4

So we have:

f(f^{-1}(-2))=f(-4)=-2

7 0
3 years ago
Read 2 more answers
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