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ArbitrLikvidat [17]

3 years ago

13

What fraction is between 4/8 and 1

2 answers:

Angelina_Jolie [31]3 years ago

7 0

Answer= 5/8, 6/8, and 7/8

There are many fractions between 4/8 and 1.

For the explanation, lets remember that 1, is equivalent to 8/8.

Comparing 4/8 and 8/8 makes answering the question easier. Since we know the fractions 5/8, 6/8 and 7/8 are between 4/8 and 1(8/8)

So three possible answers could be 5/8, 6/8, and 7/8.

aliina [53]3 years ago

5 0

There are many:

5/8
10/16
20/32
6/8
3/4
12/16
24/32
7/8
14/16
28/32
2/3

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Which of the following situations is NOT best modeled by a linear function?

GalinKa [24]

The height is not linear depending on time. Then the incorrect option is D.

<h3>What is a linear equation?</h3>

A relationship between two or more parameters that, when shown on a graph, produces a linear model. The degree of the variable will be one.

The linear equation is given as,

y = mx + c

Where m is the slope of the line and c is the y-intercept of the line.

In linear motion, the height of the object is given as,

u = √(2gh)

From the first equation on motion, we have

v = u - gt

0 = √(2gh) - gt

2h = gt²

h = gt² / 2

Thus, the height is not linear depending on time.

Then the incorrect option is D.

More about the linear equation link is given below.

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2 years ago

What is 7C3? Thanks.

Lerok [7]

Answer:

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8 0

2 years ago

Read 2 more answers

A street light is at the top of a 25 ft pole. A 4 ft tall girl walks along a straight path away from the pole with a speed of 6

Burka [1]

Answer:

Tip of the shadow of the girl is moving with a rate of 7.14 feet per sec.

Step-by-step explanation:

Given : In the figure attached, Length of girl EC = 4 ft

Length of street light AB = 25 ft

Girl is moving away from the light with a speed = 6 ft per sec.

To Find : Rate ( $\frac{dw}{dt}$ ) of the tip (D) of the girl's shadow (BD) moving away from th

light.

Solution : Let the distance of the girl from the street light is = x feet

Length of the shadow CD is = y feet

Therefore, $\frac{dx}{dt}=6$ feet per sec. [Given]

In the figure attached, ΔAFE and ΔADE are similar.

By the property of similar triangles,

$\frac{x}{21}=\frac{x+y}{25}$

25x = 21(x + y)

25x = 21x + 21y

25x - 21x = 21y

4x = 21y

y = $\frac{4x}{21}$

Now we take the derivative on both the sides,

$\frac{dy}{dt}=\frac{4}{21}\times \frac{dx}{dt}$

= $\frac{4}{21}\times 6$

= $\frac{8}{7}$

≈ 1.14 ft per sec.

Since w = x + y

Therefore, $\frac{dw}{dt}= \frac{dx}{dt}+\frac{dy}{dt}$

$\frac{dw}{dt}=6+1.14$

= 7.14 ft per sec.

Therefore, tip of the shadow of the girl is moving with a rate of 7.14 feet per sec.

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3 years ago

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mihalych1998 [28]

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IceJOKER [234]

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Step-by-step explanation:

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