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klio [65]
3 years ago
10

What is the slope of the line 4x+y=-9

Mathematics
1 answer:
olga55 [171]3 years ago
8 0

Answer:

The slope of this line is -4

Step-by-step explanation:

To find the slope, you need to solve the equation for y.

4x + y = -9

y = -4x - 9

The slope in this form is always the coefficient of x, making it -4.

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The diameter of a circular garden is 22 feet. What is the approximate area of the shaded region
SOVA2 [1]

Answer:

Step-by-step explanation:

The radius it .5 of the diameter so in this case the radius is 11.  The formula for area is pi*r^2= pi*11^2=pi*121=380.13

7 0
3 years ago
Read 2 more answers
Please help ASAP thank youu!!
Gennadij [26K]

Answer:

1. (-5)

Step-by-step explanation:

Here you go, glad to help :)

4 0
3 years ago
A carnival game has 3 identical boxes. The boxes have the following amounts of money: one has $30.00, one has $6.00, and one has
garri49 [273]
$200 divided by 100 customers = 2$.

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2 years ago
Simplify each only using positive exponents:<br> 2x^-3 • 4x^2<br> 2x^4 • 4x^-3<br> 2x^3y^-3 • 2x
erica [24]
<h2>Answer:</h2>

\frac{2}{x}

\frac{x}{2}

\frac{4x^4}{y^3}

<h2>Step-by-step explanation:</h2>

a. 2x^-3 • 4x^2

To solve this using only positive exponents, follow these steps:

i. Rewrite the expression in a clearer form

2x⁻³ . 4x²

ii. The position of the term with negative exponent is changed from denominator to numerator or numerator to denominator depending on its initial position. If it is at the numerator, it is moved to the denominator. If otherwise it is at the denominator, it is moved to the numerator. When this is done, the negative exponent is changed to positive.

In our case, the first term has a negative exponent and it is at the numerator. We therefore move it to the denominator and change the negative exponent to  positive as follows;

\frac{1}{2x^3} . 4x^2

iii. We then solve the result as follows;

\frac{1}{2x^3} . 4x^2 = \frac{2}{x}

Therefore, 2x⁻³ . 4x² = \frac{2}{x}

b. 2x^4 • 4x^-3

i. Rewrite as follows;

2x⁴ . 4x⁻³

ii. The second term has a negative exponent, therefore swap its position and change the negative exponent to a positive one.

2x^4 . \frac{1}{4x^3}

iii. Now solve by cancelling out common terms in the numerator and denominator. So we have;

\frac{x}{2}

Therefore, 2x⁴ . 4x⁻³ = \frac{x}{2}

c. 2x^3y^-3 • 2x

i. Rewrite as follows;

2x³y⁻³ . 2x

ii. Change position of terms with negative exponents;

2x^3.\frac{1}{y^3} .2x

iii. Now solve;

\frac{4x^4}{y^3}

Therefore, 2x³y⁻³ . 2x = \frac{4x^4}{y^3}

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3 years ago
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