There are 6 horses in a race. In how many ways can the first three positions of the order of the finish occur? (Assume there are
no ties)
2 answers:
120 is the answer! I hope this helps!
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Answer:
n=13
Step-by-step explanation:
3n-6=33
Add 6 to both sides
3n=39
Divide both sides by 3
n=13
Alternate exterior angles(AEA).
Given their relationship the angles are congruent.
8x-71=5x+7
3x-71=7
3x=78
X=26
I think the answer would be 57.75
I believe the answer is 4.