Answer:
Proved Below
Step-by-step explanation:

Hence, Proved that
is equivalent to
.
ANSWER
$1,413.81
EXPLANATION
The compound interest formula is given by:

Where P=900 is the balance in the account, t=10 is the number of years and r=0.0462 is the rate.
We substitute the values in to the formula to get:


This simplifies to:

Therefore $1413.81 will be in the account after 10 years.
a. The average value of
on the given interval is

b. Solve for
:
