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3 years ago

On day 1 of a savings challenge $7 was deposited. On day 8 $56 is deposited. What could be an ordered pair for this scenario?

Mathematics

1 answer:

miv72 [106K]3 years ago

8 0

An ordered pair for this scenario would be 7

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Which are correct represntions of the inequality -3(2x-5)<5(2-x)

ziro4ka [17]

Answer:

Hence x > 5.

Step-by-step explanation:

Given:-

- 3(2 x -5) < 5(2-x)

-6 x + 15 < 10 - 5 x

15 - 10 < 6 x - 5 x

5 < x

x > 5

8 0

3 years ago

14-(x+5)=3(x+9)-10 please help quick and show work!

avanturin [10]

Answer:

x=-2

Step-by-step explanation:

14-(x+5)=3(x+9)-10

14-x-5=3x+27-10

14-5-x=3x+17

+x +x

9=4x+17

-17 -17

4x=-8

4x/4=-8/4

x=-2

6 0

3 years ago

Help me guys fast as

Viktor [21]

cos(180-x)=-cosX

$\\ \rm\Rrightarrow tan^2135-cosec^260=-xcos45.sin45.cot60$

$\\ \rm\Rrightarrow (-1)^2-(\dfrac{2}{\sqrt{3}})^2=-\dfrac{x}{\sqrt{2}}\times \dfrac{1}{\sqrt{2}}\times \dfrac{1}{\sqrt{3}}$

$\\ \rm\Rrightarrow 1-\dfrac{4}{3}=\dfrac{-x}{2\sqrt{3}}$

$\\ \rm\Rrightarrow \dfrac{3-4}{3}=\dfrac{-x}{2\sqrt{3}}$

$\\ \rm\Rrightarrow \dfrac{-1}{3}=\dfrac{-x}{2\sqrt{3}}$

$\\ \rm\Rrightarrow \dfrac{1}{\sqrt{3}}=\dfrac{x}{2}$

$\\ \rm\Rrightarrow x=\dfrac{2}{\sqrt{3}}$

4 0

2 years ago

In 2015 there was a population of 155 opossums on and around the Gunn campus. The per capita birth rate in 2015 was 0.11/year an

belka [17]

Answer: 0.02 per year

Step-by-step explanation:

When given the per capita birth rate and the per capita death rate, the per capita growth rate can be calculated as:

= per capita birth rate - per capita death rate

= 0.11 - 0.09

= 0.02/year

= 2% per year

7 0

2 years ago

Exponent Laws - difference between product law and product raised to a power (with formula please)

enyata [817]

Answer:

Exponent laws:

1. Product law

$x^{a}\times x^{b}\times x^{c}=x^{a+b+c}$

In product law if bases are same then we add their respective powers.But if bases are different we can't add their powers.

x=base, a,b,c=exponent

If x=2 and a=3, b=5 , and c=10, then

$2^{3}\times2^{5}\times2^{10}=2^{3+5+10}=2^{18}$

2.Product raised to a power

1. $[x^{a}]^{c}=x^{ac}$

2. $[x^{a}\times x^{b}]^{c}=[x^{a+b}]^{c}=x^{ac+bc}$

If product is raised to a certain power , keeping the base same , we just multiply the powers.for example

$[2^{3}]^{4}=2^{3\times4}=2^{12}$ and

$[2^{3}\times3^{2}]^{2}=[2^{3}]^2 \times[3^{2}]^{2}=2^{6}\times3^{4}$

$[2^{3}\times2^{2}]^{2}=[2^{3+2}]^{2}=[2^{5}]^{2}=2^{10}$

7 0

3 years ago