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sergejj [24]
4 years ago
8

What is 256738 estimated to nearest 100000

Mathematics
1 answer:
Solnce55 [7]4 years ago
6 0
Since its more 250,000 the nearest 100,00 is
300,000 or 300000
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beach hotel in north lake tahoe is offering 2 weekend specials one includes 1 2 night stay with 3 meals and costs $195 the other
adell [148]

Answer:

$94.50

Step-by-step explanation:

2 times 9 is 18 leaves a remainder of 1

then that leaves 15 an 2 times 7 gives you 14

so that will be $94.50 for a single meal

6 0
4 years ago
1218÷6 I need help please
Morgarella [4.7K]
203 is the answer there you go
5 0
3 years ago
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XYZ is an isosceles triangle inscribed I a circle, center O. XY=XZ= 20 and YZ=18. Calculate to 3.s.f.
Vlad1618 [11]

Answer: 17.9

Step-by-step explanation:

Using Heron's formula:

Area of a triangle is given by:

√s(s-a)(s-b)(s-c)

Where a, b and c ara sides of the triangle and

S = (a+b+c) / 2

In the question above sides are :

XY=XZ= 20 and YZ=18

S = (20 + 20 + 18) / 2 = 58/2 = 29

Area = √29(29-20)(29-20)(29-18)

Area = √29(9)(9)(11)

Area = √25839

Area = 160.74513

Altitude = height(h)

Area = 0.5 × base × height

Base = yz = 18

160.74513 = 0.5 × 18 × h

160.74513 = 9 × h

h = 160.74513 / 9

h = 17.9 (3 s.f)

5 0
3 years ago
The center of a hyperbola is located at the origin. One focus is located at (−50, 0) and its associated directrix is represented
leva [86]

The equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

The center of a hyperbola is located at the origin that means at (0, 0) and one of the focus is at (-50, 0)

As both center and the focus are lying on the x-axis, so the hyperbola is a horizontal hyperbola and the standard equation of horizontal hyperbola when center is at origin: \frac{x^{2}}{a^{2}}  - \frac{y^{2}}{b^{2}}    = 1

The distance from center to focus is 'c' and here focus is at (-50,0)

So, c= 50

Now if the distance from center to the directrix line is 'd', then

d= \frac{a^{2}}{c}

Here the directrix line is given as : x= 2304/50

Thus, \frac{a^{2}}{c}  = \frac{2304}{50}

⇒ \frac{a^{2}}{50}  = \frac{2304}{50}

⇒ a² = 2304

⇒ a = √2304 = 48

For hyperbola, b² = c² - a²

⇒ b² = 50² - 48² (By plugging c=50 and a = 48)

⇒ b² = 2500 - 2304

⇒ b² = 196

⇒ b = √196 = 14

So, the equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

5 0
3 years ago
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Does anyone know how to directly ask a tutor a question? It’s like the option to is gone. Answer asap please!
tia_tia [17]

Answer:

Just find the button to ask a question. Search around for it.

Step-by-step explanation:

8 0
3 years ago
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