All categories

3 years ago

XYZ is an isosceles triangle inscribed I a circle, center O. XY=XZ= 20 and YZ=18. Calculate to 3.s.f.

Mathematics

1 answer:

Vlad1618 [11]3 years ago

5 0

Answer: 17.9

Step-by-step explanation:

Using Heron's formula:

Area of a triangle is given by:

√s(s-a)(s-b)(s-c)

Where a, b and c ara sides of the triangle and

S = (a+b+c) / 2

In the question above sides are :

XY=XZ= 20 and YZ=18

S = (20 + 20 + 18) / 2 = 58/2 = 29

Area = √29(29-20)(29-20)(29-18)

Area = √29(9)(9)(11)

Area = √25839

Area = 160.74513

Altitude = height(h)

Area = 0.5 × base × height

Base = yz = 18

160.74513 = 0.5 × 18 × h

160.74513 = 9 × h

h = 160.74513 / 9

h = 17.9 (3 s.f)

You might be interested in

Fill in the missing angle measures

Oksi-84 [34.3K]

Yo sup??

by angle sum property we know that the sum of all angles in a triangle is 180

let the unknown angle be x

then,

x+60+90=180

x=180-150

x=30

Hope this helps

7 0

4 years ago

Read 2 more answers

The CUBE ROOT of a number is -1. What is the number? *

romanna [79]

Answer:

The number is -1

6 0

3 years ago

Read 2 more answers

Cecily made a poster in the shape of a quadrilateral

Sholpan [36]

And what else, add more detail so i can answer

4 0

3 years ago

On average, a person’s heart beats about 4.2×107 times per year. There are about 7,600,000,000 people in the world. Use this dat

gayaneshka [121]

Answer:

a=3.192 b=17

Step-by-step explanation:

I just used a graphing calculator to multiply the req. numbers

5 0

3 years ago

Find the product. (r s)2 r² 2rs s r² 2rs s² r² 2rs 2s².

sveta [45]

The product of the given expression is $\rm 2r^3+ s^3r^3+ 2r^3s + sr^3+ 2s^3+ 6rs$ .

Given

The product of $\rm 2r^2(r + s) + 2rs + s^2 + 2rs + s^2r^2+ 2rs + 2s^2$ .

<h3>What is multiplication?</h3>

Multiplication is the process of calculating the product of two or more numbers.

The multiplication of numbers say, ‘a’ and ‘b’, is stated as ‘a’ multiplied by ‘b’.

The product of $\rm 2r^2(r + s) + 2rs + s^2 + 2rs + s^2r^2+ 2rs + 2s^2$ is given by;

$\rm 2r^2(r + s) + 2rs + s^2 + 2rs + s^2r^2+ 2rs + 2s^2\\\\(2r^3 + 2r^2s) + 2rs + 2rs + 2rs + s^2r^2 + sr^2 + 2s^2\\\\2r^3+ 2r^2s + 6rs + s^2r^2 + sr^2+ 2s^2$

$\rm 2r^3+ s^3r^3+ 2r^3s + sr^3+ 2s^3+ 6rs$

Hence, the product of the given expression is $\rm 2r^3+ s^3r^3+ 2r^3s + sr^3+ 2s^3+ 6rs$ .

To know more about Multiplication click the link given below.

brainly.com/question/19943359

6 0

2 years ago