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timurjin [86]
3 years ago
12

Determine if ƒ(x) = 3x2 – 2x3 – x – 9 is a polynomial function. If it is, state the degree and the leading coefficient. If not,

state why.
Mathematics
2 answers:
kogti [31]3 years ago
7 0

Answer:  The given function is a polynomial function with leading coefficient -2.

Step-by-step explanation:  We are given to determine whether the following function is a polynomial function :

f(x)=3x^2-2x^3-x-9.

If yes, we are to state the degree and the leading coefficient. If not, we are to state the reason.

 We know that

any polynomial function is of the form :

p(x)=a_nx^n+a_{n-1}x^{n-1}+a_{n-2}x^{n-2}+~~.~~.~~.~~+a_1x+a_0,

with degree n.

Son according to this definition, the given function f(x) is a polynomial function with degree 3.

The standard form of the given polynomial function is:

f(x)=-2x^3+3x^2-x-9.

Since the leading coefficient is the coefficient of the highest power of x, so the leading coefficient is -2.

Thus, the given function is a polynomial function with leading coefficient -2.

adelina 88 [10]3 years ago
3 0
This is indeed a polymomial, it's just not in the correct order.  The term with the highest exponent goes first, dictating the degree of the whole entire polynomial.  In descending order, the polynomial is written correctly as -2x^3+3x^2-x-9.  It is a third degree polynomial with a leading coefficient of -2. 
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(ASAP) Billie & Tony are siblings. It’s summer of 2015. Twice Billie’s age decreased by 3 is Tony’s age. Tony is fourteen ye
jeka94

Answer:

Billie's age = x = 17 years

Tony's age = y = 31 years

Step-by-step explanation:

Let

Billie's age = x

Tony's age = y

Twice Billie’s age decreased by 3 is Tony’s age.

y = 2x - 3..... Equation 1

Tony is fourteen years older than Billie.

x = y - 14

We substitute y - 14 for x in Equation 1

y = 2x - 3..... Equation 1

y = 2(y - 14) - 3

y = 2y - 28 - 3

y - 2y = -28 - 3

-y = -31

y = 31 years

Solving for x

x = y - 14

x = 31 - 14

x = 17 years.

Therefore:

Billie's age = x = 17 years

Tony's age = y = 31 years

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