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bearhunter [10]
3 years ago
11

Can you show me this step by step please

Mathematics
1 answer:
Leya [2.2K]3 years ago
5 0

Answer:

  clockwise from left, the missing side lengths are 8 m, 13 m, 8 m

Step-by-step explanation:

The perimeter of the figure is the sum of the lengths of its sides. Sides with the same hash mark have the same length, so the perimeter (in meters) is ...

  38 = (3x+1) +(2x) +(9) +(2x)

  38 = 7x +10

  28 = 7x . . . . . . subtract 10

  4 = x . . . . . . . . divide by 7

Then the short sides are ...

  2x = 2·4 = 8 . . . meters

and the long side is ...

  3x+1 = 3·4 +1 = 13 . . . meters

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A certain bookstore chain has two stores, one in San Francisco and one in Los Angeles. It stocks three kinds of books: hardcover
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Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

(a)

\left[\begin{array}{cccc}T&H&S&P\\S&600&1300&2000\\L&400&300&400\end{array}\right] = A.

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Hence, 6A = \left[\begin{array}{cccc}T&H&S&P\\S&3600&7800&12000\\L&2400&1800&2400\end{array}\right]. This matrix 6A represents the total sales over the 6 months.

(b)

If we denote the books in stock at the starting of January by B, then

B = \left[\begin{array}{cccc}T&H&S&P\\S&1000&3000&6000\\L&1000&6000&3000\end{array}\right].

Each month, the chain restocked the stores from its warehouse by shipping 500 hardcover, 1,400 softcover, and 1,400 plastic books to San Francisco and 500 hardcover, 500 softcover, and 500 plastic books to Los Angeles.

If we represent the amount restocked books at the end of each month by another matrix C, then

C = \left[\begin{array}{cccc}T&H&S&P\\S&500&1400&1400\\L&500&500&500\end{array}\right].

This restocking will be done for 5 times before the end of June.

If there would be no sale, then the stock would be

B + 5C = \left[\begin{array}{cccc}T&H&S&P\\S&1000+2500&3000+7000&6000+7000\\L&1000+2500&6000+2500&3000+2500\end{array}\right] \\= \left[\begin{array}{cccc}T&H&S&P\\S&3500&10000&13000\\L&3500&8500&5500\end{array}\right].

Since, the total sale is given by 6A, at the end of June, the inventory in each store can be shown as following,

B+5C-6A \left[\begin{array}{cccc}T&H&S&P\\S&3500&10000&13000\\L&3500&8500&5500\end{array}\right] - \left[\begin{array}{cccc}T&H&S&P\\S&3600&7800&12000\\L&2400&1800&2400\end{array}\right] \\= \left[\begin{array}{cccc}T&H&S&P\\S&-100&2200&1000\\L&1100&6700&3100\end{array}\right]

6 0
2 years ago
-p/3 - 8 = -3 I need the show work too
professor190 [17]

Answer:

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Find the value of the variable that results in congruent triangles for numbers 6 and 8.
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Answer:

x = 28

Step-by-step explanation:

From the figure attached,

AC ≅ FH [Given]

BC ≅ GH [Given]

AB ≅ FG [Given]

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Since, m∠A + m∠B + m∠C = 180°

50° + 69° + m∠C = 180°

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m∠C = m∠H [Since, ΔABC ≅ ΔFGH]

(2x + 5)° = 61°

2x = 61 - 5

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