Here, it is given that the bag contains 25 paise coins and 50 paise coins in which, 25 paise coins are 6 times than that of 50 paise coins. Also, the total money in the bag is Rs. 6.

Hence, we can see that, here, we have been given the linear equation be;

Let the number of coins of 50 paise will be $ x $ and the number of coins of 25 paise will be $ 6x $ as given. . .

Hence,

$x + 6x = 6$

$7x = 6$

$x = \frac{6}{7} \\$

$x = 1.1666667 \approx \: 2$

Hence, the number of 50 paise coins will be <u>2</u>. And, 6 times of two be;

$6(2)$

Hence, the number of 25 paise coins will be <u>12</u>.

6 0

3 years ago

Find all 6 trig functions given the terminal side goes through point (0,-3)

d1i1m1o1n [39]

So hmm notice the picture below

that's (0, -3)

now, keep in mind, adjacent is 0, opposite is -3, and hypotenuse, or radius, is 3

and recall $sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad \qquad 
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}

\\ \quad \\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{adjacent}{opposite}
\\ \quad \\

% cosecant
csc(\theta)=\cfrac{hypotenuse}{opposite}
\qquad \qquad 
% secant
sec(\theta)=\cfrac{hypotenuse}{adjacent}$

8 0

3 years ago

Maria bought a bag of mixed fruit that is 40% oranges, 33% green apples, and 27% red apples, If she

motikmotik

Answer: B

Explanation

4 0

3 years ago

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