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4 years ago

A line has a slope of 4 and passes through the point (2, 6). What is the equation in slope-intercept form?

Mathematics

1 answer:

Marrrta [24]4 years ago

8 0

Answer:

y=4x-2

Step-by-step explanation:

y=mx+b

where m=slope and b=y-intercept.

y-6=4(x-2)

y-6=4x-8

y=4x-8+6

y=4x-2

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Select the correct answer.

Butoxors [25]

Answer:

Hello there the Correct answer The only answer choice that produces -2x²+2 is D.

Because (-x²+2x+3)+(-x²-2x-1) = -x²+2x+3-x²-2x-1 = -2x²+2

answer: D

Hope It Helps!

5 0

3 years ago

Sangeet got 96% of his answers right in a test of 50 marks. What was his score out of 50?

Ulleksa [173]

Answer:

48 out of 50 correct answers

8 0

3 years ago

I have nooooo clue, please help

Aleksandr-060686 [28]

Answer:

case a) $x^{2}=3y$ ----> open up

case b) $x^{2}=-10y$ ----> open down

case c) $y^{2}=-2x$ ----> open left

case d) $y^{2}=6x$ ----> open right

Step-by-step explanation:

we know that

1) The general equation of a vertical parabola is equal to

$y=a(x-h)^{2}+k$

where

a is a coefficient

(h,k) is the vertex

If a>0 ----> the parabola open upward and the vertex is a minimum

If a<0 ----> the parabola open downward and the vertex is a maximum

2) The general equation of a horizontal parabola is equal to

$x=a(y-k)^{2}+h$

where

a is a coefficient

(h,k) is the vertex

If a>0 ----> the parabola open to the right

If a<0 ----> the parabola open to the left

Verify each case

case a) we have

$x^{2}=3y$

$y=(1/3)x^{2}$

$a=(1/3)$

$a>0$

therefore

The parabola open up

case b) we have

$x^{2}=-10y$

$y=-(1/10)x^{2}$

$a=-(1/10)$

$a$

therefore

The parabola open down

case c) we have

$y^{2}=-2x$

$x=-(1/2)y^{2}$

$a=-(1/2)$

$a$

therefore

The parabola open to the left

case d) we have

$y^{2}=6x$

$x=(1/6)y^{2}$

$a=(1/6)$

$a>0$

therefore

The parabola open to the right

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