Ask question

Ask question

All categories

3 years ago

14

Which equations are equivalent to y = two-thirds x minus 4 when written in slope-intercept form? Check all that apply.

2 answers:

Nikitich [7]3 years ago

5 0

Answer:

B an C is the answer

Step-by-step explanation:

I HOPE THIS HELPS!

I TOOK THE QUIZ ON Edge

mixas84 [53]3 years ago

5 0

Answer:

B) & C).

Step-by-step explanation:

Free points UuU.

You might be interested in

N is the set of odd natural numbers greater than 11 and less than 21. Use set notation to write the elements of N. N

S_A_V [24]

Answer:

N = {13, 15, 17, 19}

Step-by-step explanation:

The natural numbers greater than 11 and less than 21 are:

12, 13, 14, 15, 16, 17, 18, 19 and 20

Odd numbers are numbers that have remainders when divided by 2. Out of the numbers above, the numbers with remainders when divided by 2 are 13, 15, 17 and 19.

Since N is the set of odd natural numbers greater than 11 and less than 21,

N = {13, 15, 17, 19}

4 0

3 years ago

Read 2 more answers

In 12 seconds, Valerie counts 6 vehicles passing by her house. At that rate, how many vehicles would pass by in 4 hours

mart [117]

60/12
30 * 4 = 110 cars

5 0

3 years ago

Hey Bestie! 50 pts Pls help! Real answers only pls <3

frosja888 [35]

Answer:

$1. \: 3i$

2. option D

3. option C

4. option D

5. option C

6. option B

7. option C

8. option D

9. option C

10. option C

Step-by-step explanation:

<h2> $1. \: \sqrt{ - 9}$ </h2>

$\sqrt{ - 1(9)}$

$\sqrt{ - 1} \times \sqrt{ 9}$

$i \times \sqrt{9}$

$i \times \sqrt{ {3}^{2} }$

$i \times 3$

$3i$

<h2> $2. \: \sqrt{ - 8}$ </h2>

$\sqrt{ - 1(8)}$

$\sqrt{ - 1} \times \sqrt{8}$

$i \times \sqrt{8}$

$i \times \sqrt{ {2}^{2} \times 2 }$

$2i \sqrt{2}$

<h2> $3. \: \sqrt{ - 80}$ </h2>

$\sqrt{ - 1} \times \sqrt{80}$

$i \times \sqrt{80}$

$4i \: \sqrt{5}$

<h2> $4. \: \sqrt{ - 75}$ </h2>

$\sqrt{ - 1} \times \sqrt{75}$

$i \times \sqrt{75}$

$i \times \sqrt{ {5}^{2} \times 3 }$

$5i \sqrt{3}$

<h2> $5. \: \sqrt{ - 72}$ </h2>

$\sqrt{ - 1} \times \sqrt{72}$

$i \times \sqrt{72}$

$i \times ( {6}^{2} \times 2)$

$6i \sqrt{2}$

<h2> $6. \sqrt{ - 20}$ </h2>

$\sqrt{ - 1} \times \sqrt{20}$

$i \times \sqrt{20}$

$i \times \sqrt{ {2}^{2} \times 5}$

$2i \sqrt{5}$

<h2> $7. \: \sqrt{ - 27}$ </h2>

$\sqrt{ - 1} \times \sqrt{27}$

$i \times \sqrt{27}$

$i \times \sqrt{ {3}^{2} \times 3}$

$3i \sqrt{3}$

<h2> $8. \: \sqrt{ - 12}$ </h2>

$\sqrt{ - 1 \times 12}$

$i \times \sqrt{12}$

$i \times \sqrt{4(3)}$

$2i \sqrt{3}$

<h2> $9. \: \sqrt{ - 125}$ </h2>

$\sqrt{ - 1} \times \sqrt{125}$

$i \times \sqrt{ {5}^{2} \times 5 }$

$5i \sqrt{5}$

<h2> $10. \: \sqrt{ - 180}$ </h2>

$\sqrt{ - 1} \times \sqrt{180}$

$i \times \sqrt{ {6}^{2} \times 5 }$

$6i \sqrt{5}$

<h3>Hope it is helpful...</h3>

5 0

3 years ago

14x + 54 = 11x + 96 x=

jenyasd209 [6]

Move the 11x to the left and the +54 to the right. Their signs will flip:

14x-11x = 96-54
3x = 42
x = 14

4 0

3 years ago

Read 2 more answers

According to the rational root theorem, which of the following are possible

White raven [17]

Given:

The polynomial function is

$F(x)=4x^3-6x^2+9x+10$

To find:

The possible roots of the given polynomial using rational root theorem.

Solution:

According to the rational root theorem, all the rational roots and in the form of $\dfrac{p}{q}$ , where, p is a factor of constant and q is the factor of leading coefficient.

We have,

$F(x)=4x^3-6x^2+9x+10$

Here, the constant term is 10 and the leading coefficient is 4.

Factors of constant term 10 are ±1, ±2, ±5, ±10.

Factors of leading term 4 are ±1, ±2, ±4.

Using rational root theorem, the possible rational roots are

$x=\pm 1+,\pm 2, \pm 5, \pm 10,\pm \dfrac{1}{2}, \pm \dfrac{5}{2}, \dfrac{1}{4}, \pm \dfrac{5}{4}$

Therefore, the correct options are A, C, D, F.

7 0

3 years ago