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yawa3891 [41]
2 years ago
11

Solve for n nn. 7 n − 4 = 31

Mathematics
2 answers:
never [62]2 years ago
8 0

{ \longmapsto{ \sf{7n - 4 = 31}}}

{ \longmapsto{ \sf{7n  =  31 + 4}}}

{ \longmapsto{ \sf{7n  =  35}}}

{ \longmapsto{ \sf{n =  \frac{35}{7} }}}

{ \longmapsto{ \sf{n =   \cancel\frac{35}{7} }}}

{ \color{blue}{ \longmapsto{ \sf{n = 5 }}}}

<h2><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u></h2>

makkiz [27]2 years ago
5 0

Answer: 5

Step-by-step explanation:

5x7=35

35-4=31

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A system for tracking ships indicated that a ship lies on a hyperbolic path described by 5x2 - y2 = 20. the process is repeated
zysi [14]
Answer:
The ship is located at (3,5)

Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III

Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II

To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.

Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9

We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3

Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5

Based on the above, the position of the ship is (3,5).

Hope this helps :)
8 0
2 years ago
Jensen has an above ground pool in the shape of a regular octagon. Opposite sides are 25 feet apart and each side is 10.4 feet l
bija089 [108]

Answer:

<u>Given</u>: base = 10.4ft, height = 12.5

Area of octagon = 8(1/2 × b × h)

  • 8(1/2 × 10.4 × 12.5)
  • 520ft²

Volume of pool = 520ft² × 3ft

  • 1560ft³

Now, 1 cubic ft takes 7.5 gallons to fill.

Therefore, 1560 cubic ft takes,

  • 1560 × 7.5
  • 11700

So, <u>Correct choice</u> - [D] 11,700.

6 0
3 years ago
Y = –6x+2
qwelly [4]
The answer is Infinate Solutions I believe we are working on these types of equations in school rn
5 0
3 years ago
Read 2 more answers
How many titles 250mm square will be needed to cover s kitchen floor of length 3m and breath 2.5m . The answer should be in the
nordsb [41]

Answer:

30,000 tiles

Step-by-step explanation:

Area of tile = 250mm^2 = 0.25m^2

Total area of kitchen = 3*2.5 = 7.5m^2

No of tiles = 7.5/0.25 = 30,000 tiles

6 0
2 years ago
Tony buys 2 boxes of chocolates. One is 4 in. 7 in. 8 in. And 8 in. 5 in. 6 in. Which box has the larger volume?
Rufina [12.5K]

Answer:

Second box

Step-by-step explanation:

Volume (of the box) = length * width * height

Volume of first box is: 4 * 7 * 8 = 224

Volume of second box is: 8 * 5 * 6 = 240

Since 224 < 240, the volume of the second box has the larger value.

4 0
2 years ago
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