Answer:
The answer is option D
g(x) = |x+3|
Step-by-step explanation:
Please see attached graph
The changes made to the function result from translating the graph of f(x) three units to the left
By substituting the equations provided at x = -3 and x = 0 respectively, we can find the same value for both functions.
g(x = -3) = |(-3)+3| = |0| = 0
f(x = 0) = |0| = 0
Answer-
The exponential model best fits the data set.
Solution-
x = input variable = number of practice throws
y = output variable = number of free throws
Using Excel, Linear, Quadratic and Exponential regression model were generated.
The best fit equation and co-efficient of determination R² are as follows,
Linear Regression
Quadratic Regression
Exponential Regression
The value of co-efficient of determination R² ranges from 0 to 1, the more closer its value to 1 the better the regression model is.
Now,
Therefore, the Exponential Regression model must be followed.
Answer:
The answer for y is 4 units
Step-by-step explanation:
The obvious question to ask in this situation is, “how many miles does Joseph travel on Mondays”? To compute, we each distance: 3 + 6 + 6 = 15.
Joseph travels 15 miles on Mondays.
Another way to work with this situation is to draw a shape that represents Joseph’s travel route and is labeled with the distance from one spot to another.
Notice that the shape made by Joseph’s route is that of a closed geometric figure with three sides (a triangle) (see figure 2). What we can ask about this shape is, “what is the perimeter of the triangle”?
Perimeter means “distance around a closed figure or shape” and to compute we add each length: 3 + 6 + 6 = 15
Our conclusion is the same as above: Joseph travels 15 miles on Mondays.
However, what we did was model the situation with a geometric shape and then apply a specific geometric concept (perimeter) to computer how far Joseph traveled.
Answer:
The area of trapezoid is 20 square centimeters
Step-by-step explanation:
Let
x -----> the length of rectangle
y ----> the height of rectangle
h ----> height of trapezoid
Applying the Trapezoid Mid-segment Theorem we have that
----> equation A
---->
----> equation B
Remember that
The area of rectangle is equal to

The area of trapezoid is equal to
-----> equation C
substitute equation A and equation B in equation C

The area of trapezoid is two times the area of rectangle
therefore
The area of trapezoid is 20 square centimeters