Let t hours be the number of hours needed for the second train to catch up the first one.
Then the first train is on the way (t+1) hours.
1. First train travels at a speed of 60 mph (t+1) hours and passes

2. Second train travels at a speed of 70 mph t hours and passes

Since two trains will meet, then

Then they will meet at 7:00 p.m.
Answer: 7:00 p.m.