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Cloud [144]
3 years ago
15

What value represents the vertical translation from the graph of the parent function f(x)=x? to the graph of the

Mathematics
1 answer:
AnnyKZ [126]3 years ago
7 0

Answer:

can you give a screen shot?

Step-by-step explanation:

need more explanation please

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WILL GIVE BRAINLIEST!!
VMariaS [17]

Answer:

A(-1,4)\to A''(-1,-1)

B(0,2)\to B''(1,0)

C(1,2)\to C''(1,1)

D(-2,4)\to D''(-1,2)

Step-by-step explanation:

The given trapezoid has vertices at A(−1,4), B(0,2), C(1,2) and D(2,4).

The transformation rule for 90° counterclockwise rotation is

(x,y)\to(-y,x)

This implies that:

A(-1,4)\to A'(-4,-1)

B(0,2)\to B'(-2,0)

C(1,2)\to C'(-2,1)

D(2,4)\to D'(-4,2)

This is followed by a translation 3 units to the right.

This also has the rule: (x,y)\to (x+3,y)

A'(-4,-1)\to A''(-1,-1)

B'(-2,0)\to B''(1,0)

C'(-2,1)\to C''(1,1)

D'(-4,2)\to D''(-1,2)

Therefore:

A(-1,4)\to A''(-1,-1)

B(0,2)\to B''(1,0)

C(1,2)\to C''(1,1)

D(-2,4)\to D''(-1,2)

3 0
4 years ago
Estimate 8 x 342 Jehhdhd
V125BC [204]

Answer:

2,736

Step-by-step explanation:

5 0
3 years ago
Can someone please help me with this problem...thanks
makkiz [27]

Answer:

41/15

Step-by-step explanation:

I don't know

8 0
3 years ago
Which shows all the like terms in the expression?
GenaCL600 [577]
4x-3+7x+1

Ones with a variable: 4 & 7
Only whole number: -3 & 1

The answer is option two: -3 and 1; 4x and 7x
7 0
3 years ago
Read 2 more answers
Box of 15 gadgets is known to contain 5 defective gadgets if 4 gadgets are drawn at random what is the probability of finding no
baherus [9]

To solve this problem, we make use of the Binomial Probability equation which is mathematically expressed as:

P = [n! / r! (n – r)!] p^r * q^(n – r)

where,

n = the total number of gadgets = 4

r = number of samples = 1 and 2 (since not more than 2)

p = probability of success of getting a defective gadget

q = probability of failure = 1 – p

 

Calculating for p:

p = 5 / 15 = 0.33

So,

q = 1 – 0.33 = 0.67

 

Calculating for P when r = 1:

P (r = 1) = [4! / 1! 3!] 0.33^1 * 0.67^3

P (r = 1) = 0.3970

 

 

Calculating for P when r = 2:

P (r = 2) = [4! / 2! 2!] 0.33^2 * 0.67^2

P (r = 2) = 0.2933

 

Therefore the total probability of not getting more than 2 defective gadgets is:

P = 0.3970 + 0.2933

P = 0.6903

 

Hence there is a 0.6903 chance or 69.03% probability of not getting more than 2 defective gadgets.

5 0
4 years ago
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