Answer:
You would have $343.37 at the end of the 2 years.
Step-by-step explanation:
Interest earned is like bonus money the bank pays you just for keeping money
P: the starting balance of the account (also called initial deposit, or principal)
A: the new balance in the account after N years.
t: the number of years or time
r: the interest rate, (in decimal form)
n: the number of times the interest is compounded each year.
Annually = each year = 1
P =$300, r = 7%, t = 2, n = 1, A = ?
Substitute the numbers into the "Compound Interest Formula".
So you would have $343.37 at the end of the 2 years.
Look at the chart
Hello,
tan KLJ=6/8=3/4
=> mes angle KLJ=36.8698976558...°≈36.87 °
Answer B.
Answer:
In 1981, the Australian humpback whale population was 350
Po = Initial population = 350
rate of increase = 14% annually
P(t) = Po*(1.14)^t
P(t) = 350*(1.14)^t
Where
t = number of years that have passed since 1981
Year 2000
2000 - 1981 = 19 years
P(19) = 350*(1.14)^19
P(19) = 350*12.055
P(19) = 4219.49
P(19) ≈ 4219
Year 2018
2018 - 1981 = 37 years
P(37) = 350*(1.14)^37
P(37) = 350*127.4909
P(37) = 44621.84
P(37) ≈ 44622
There would be about 44622 humpback whales in the year 2018
Answer:
the ansrew is 3%
Step-by-step explanation:
160 divided by 32= 3% mostly around 3.3125 i am not 100% sure so u should probably wait for someone else but this is my way of seeing the problem.
29440 divided by 2 equals 14,720
