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madam [21]
3 years ago
15

Mr. Alexander had a negative bank account balance of -$50. He went out to dinner, and spent $23.73. The balance in Mr. Alexander

's bank account is now:
Mathematics
2 answers:
ollegr [7]3 years ago
6 0

Answer:

-$73.73

Step-by-step explanation:

To get this answer, we must subtract 23.73 from -50, as Mr. Alexander is losing money by spending. Once we subtract, we get -73.73 dollars.

Hope this helps!

aleksandr82 [10.1K]3 years ago
6 0

Answer:

-$73.73

Step-by-step explanation:

His bank account had a balance of -50

Now, after he spent 23.73, he has -$50 - $23.73.

-$50 - $23.73 = -$73.73

The balance in Mr. Alexander's bank account is now: -$73.73

Hope this helps :)

Have an awesome day!

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A right triangle has a leg of 12 cm and a hypotenuse of 19 cm.
Yakvenalex [24]

Answer:

14.7 cm

Step-by-step explanation:

Using Pythagoras Theorem,

The length of the other leg

=  \sqrt{ {19}^{2}  -  {12}^{2} }

=  \sqrt{217}

= 14.730919...

= 14.7 cm (rounded to the nearest tenth)

6 0
3 years ago
Give the standard form for 80.000 + 200 + 2.
Masja [62]
80202 that’s the answer
8 0
3 years ago
How can I calculate if a given decimal is rational or irrational. please help I forgot.
dalvyx [7]
Well, a rational decimal is like a simple 3.1 or 4.5. It just cuts off easily. Another example would be a repeating decimal like 3.333333...


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4 0
3 years ago
EXTRA POINTS!
antiseptic1488 [7]

Answer:

y = 15

Step-by-step explanation:

angle poq + angle qor equals mpor (120)

4y + 3y + 15= 120

7y+15=120

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7y=150

divide both sides by 7

y=15

check:

4(15) + 3(15) + 15 equals 120

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7 0
3 years ago
Let v be an eigenvector of a matrix A with a corresponding eigenvalue ?=2. Find one solution x of the system Ax=v.
Murljashka [212]

Answer with explanation:

For, a Matrix A , having eigenvector 'v' has eigenvalue =2

 The order of matrix is not given.

It has one eigenvalue it means it is of order , 1×1.

→A=[a]

Determinant [a-k I]=0, where k is eigenvalue of the given matrix.

It is given that,

k=2

For, k=2, the matrix [a-2 I] will become singular,that is

→ Determinant |a-2 I|=0

→I=[1]

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Let , v be the corresponding eigenvector of the given eigenvalue.

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→[2-1] v=[0]

→[v]=[0]

→v=0

Now, corresponding eigenvector(v), when eigenvalue is 2 =0

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→Ax=v

→[2] x=0

→[2 x] =[0]

→x=0, is one solution of the system.

5 0
4 years ago
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