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miskamm [114]
4 years ago
8

The height of a tree in feet over x years is modeled by the function f(x).

Mathematics
2 answers:
timama [110]4 years ago
8 0

Answer:

Just took the test and the answers are: The trees maximum height

is limited to 30ft, After growing 15ft the trees rate of growth decreases, and between the 5th and 7th years the tree grows approximately 7ft.

SVEN [57.7K]4 years ago
6 0
The following statements are true:
The tree grows approximately 7 feet between years 5 and 7; 
the tree stops growing at around 30 feet

In graphing the function, we see that the initial value, when x = 0, is 1 ft, not 2.
Additionally, we can see the values as the height increases; when the tree hits 15 feet, it continues to grow at around 1.5 feet every 0.4 years until it hits around 25 feet tall.  Then it begins to slow down.
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Answer:

<h2>A = 20</h2><h2>P = 6√10</h2>

Step-by-step explanation:

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

A(-3, 0) , B(3, 2)

AB=\sqrt{(3-(-3))^2+(2-0)^2}=\sqrt{6^2+2^2}=\sqrt{36+4}=\sqrt{40}=\sqrt{4\cdot10}=\sqrt4\cdot\sqrt{10}=2\sqrt{10}

A(-3, 0), D(-2, -3)

AD=\sqrt{(-2-(-3))^2+(-3-0)^2}=\sqrt{1^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}

AB = CD and AD = BC

The area of a rectangle:

A=(AB)(AD)

Substitute:

A=(2\sqrt{10})(\sqrt{10})=(2)(10)=20

The perimeter of a rectangle:

P=2(AB+AD)

Substitute:

P=2(2\sqrt{10}+\sqrt{10})=2(3\sqrt{10})=6\sqrt{10}

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