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ozzi
2 years ago
5

Suppose you are given Circle B with Area of ΔAOB(purple) = Area of Sector BOC (pink). What is m

Mathematics
1 answer:
Art [367]2 years ago
8 0
\bold{ANSWER:}

28.65 Degrees

\bold{EXPLANATIONS:}

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Suppose box A contains 4 red and 5 blue poker chips and box B contains 6 red and 3 blue poker chips. Then a poker chip is chosen
sergejj [24]

Answer:

0.5172 = 51.72% probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Coin chosen from box B is red.

Event B: Blue poker chip transferred.

Probability of choosing a red coin:

7/10 of 4/9(red coin from box A)

6/10 of 5/9(blue coin from box A). So

P(A) = \frac{7}{10}*\frac{4}{9} + \frac{6}{10}*\frac{5}{9} = \frac{28 + 30}{90} = 0.6444

Blue chip transferred, red coin chosen:

6/10 of 5/9. So

P(A \cap B) = \frac{6}{10}*\frac{5}{9} = \frac{30}{90} = 0.3333

What is the probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.3333}{0.6444} = 0.5172

0.5172 = 51.72% probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red

5 0
3 years ago
What is the sum of 36 plus 25
bija089 [108]
The sum is 61 for this equation.
5 0
3 years ago
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Find all values of x such that <img src="https://tex.z-dn.net/?f=%5Csqrt%7B4x%5E2%7D%20-%5Csqrt%7Bx%5E2%7D%3D%206" id="TexFormul
tester [92]
There are two answers.
6 and -6
3 0
3 years ago
Plz help me i'm lost badly
Annette [7]

Answer:

Im not sure but i think the answer is 0

3 0
3 years ago
I need to know the equations
dem82 [27]
Let l, t, b represent the numbers of lions, tigers, bears, respectively.

2l +3t +3b = 156 . . . . . . . 156 meals per day are supplied
l +t = 3b . . . . . . . . . . . . . . there are 3 times as many great cats as bears
l +t +b = 68 . . . . . . . . . . . there are a total of 68 animals

_____
The last 2 equations tell you
.. 4b = 68
.. b = 17
Subtracting 3 times the last equation from the first gives
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There are 48 lions, 3 tigers, and 17 bears.
4 0
3 years ago
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