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3 years ago

5

Suppose you are given Circle B with Area of ΔAOB(purple) = Area of Sector BOC (pink). What is m

1 answer:

Art [367]3 years ago

8 0

$\bold{ANSWER:}$

28.65 Degrees

$\bold{EXPLANATIONS:}$

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A truck going 50 miles per hour

larisa86 [58]

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133.33 mph

Step-by-step explanation:

The small trick is to notice the time. Is it 8:00 AM the same day. We don't know, but we will assume it is.

So the truck was on the road for 2 hours.

The car was on the road for 2 - 1/2 = 1 1/2 = 1.5 hours.

The distance travelled was 200 miles

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3 years ago

Travis jogged to his friend's house 10 miles away and then got a ride back home. It took him 2 hours longer to jog there than ri

spin [16.1K]

Using the relation between velocity, distance and time, it is found that his jogging rate was of 4.5 mph.

<h3>What is the relation between velocity, distance and time?</h3>

Velocity is <u>distance divided by time,</u> hence:

$v = \frac{d}{t}$

Jogging, his velocity was of v, while the time was of t + 2, for a distance of 10 miles, hence:

$v = \frac{10}{t + 2}$

Riding, his velocity was of 16, while the time was of t, also for a distance of 10 miles, hence:

$v + 16 = \frac{10}{t}$

Then, considering the first equation and replacing in the second:

$\frac{10}{t + 2} + 16 = \frac{10}{t}$

$\frac{10}{t} - \frac{10}{t + 2} = 16$

$\frac{10t + 20 - 10t}{t(t + 2)} = 16$

16t² + 32t - 20 = 0 -> t = 0.5.

Then his jogging rate in mph was:

$v = \frac{10}{0.5 + 2} = 4.5$

More can be learned about the relation between velocity, distance and time at brainly.com/question/24316569

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2 years ago