The height at time t is
h(t) = 144 - 16t²
When t = 0, then h = 144.
Therefore the height from the ground is 144 when the object is dropped.
When the object reaches the ground, h = 0.
Therefore
144 - 16t² = 0
t² = 144/16 = 9
t = 3 s
Answer:
The object reaches the ground in 3 seconds.
Subtract X
2y=-x+6
Then divide by 2
Y=-1/2x+3
From the given statement, we know the following...
0.35x = $247 where x = the orginial number
So if we solve for x by dividing by 0.35
x = $247/0.35 = $705.71
