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meriva
3 years ago
5

What muiltply goes into 17 80

Mathematics
2 answers:
Tomtit [17]3 years ago
8 0
Multiples of 17 and 80 is 4,2
maxonik [38]3 years ago
5 0
2 x 890 = 1780 4 x 445 5 x 356 10 x 178 20 x 89 Which are all equal to 1780.
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Calculate the surface area of the object below
Yakvenalex [24]

Answer:

<h2>351. 86 yd² </h2>

Step-by-step explanation:

As = 2πrh + 2πr²

where r = 4,  h = 10

plugin values into the equation:

As = 2π (4) 10 + 2 π (4)²

As = 251.33 + 100.53

As = 351. 86 yd²

8 0
3 years ago
Find the sum of the first 12 terms of the sequence. Show all work for full credit. 1, -4, -9, -14, . . . (2 points)
My name is Ann [436]

<u>Answer:</u>

S_n= -348

<u>Step-by-step explanation:</u>

We are given the following arithmetic sequence and we are to find the sum of its first 12 terms:

1, -4, -9, -14, . . .

For that, we will use the formula for the sum of the arithmetic mean:

S_n=\frac{n}{2} (a_1+a_n)

We know the value of the first term (a_n) but we need to find the value of a_{12}. So we will use the following formula:

a_{12}=a_1+(n-1)d

a_{12}=(-4)+(12-1)(5)

a_{12}=-59

Substituting these values in the sum formula to get:

S_n=\frac{12}{2} (1+(-59))

S_n= -348

4 0
3 years ago
Read 2 more answers
Which of the following is not a property of a chi-square distribution?
laiz [17]

Answer:

c) Is not a property (hence (d) is not either)

Step-by-step explanation:

Remember that the chi square distribution with k degrees of freedom has this formula

\chi_k^2 = \matchal{N}_1^2 +  \matchal{N}_2^2 + ... + \, \matchal{N}_{k-1}^2 +  \matchal{N}_k^2

Where N₁ , N₂m .... N_k are independent random variables with standard normal distribution. Since it is a sum of squares, then the chi square distribution cant take negative values, thus (c) is not true as property. Therefore, (d) cant be true either.

Since the chi square is a sum of squares of a symmetrical random variable, it is skewed to the right (values with big absolute value, either positive or negative, will represent a big weight for the graph that is not compensated with values near 0). This shows that (a) is true

The more degrees of freedom the chi square has, the less skewed to the right it is, up to the point of being almost symmetrical for high values of k. In fact, the Central Limit Theorem states that a chi sqare with n degrees of freedom, with n big, will have a distribution approximate to a Normal distribution, therefore, it is not very skewed for high values of n. As a conclusion, the shape of the distribution changes when the degrees of freedom increase, because the distribution is more symmetrical the higher the degrees of freedom are. Thus, (b) is true.

6 0
3 years ago
Nine times the sum of a number and 8 is 7
Sladkaya [172]

this is the equation x+9+8=7

5 0
3 years ago
Solve the following equation for y: 4x - 2y = 10
katrin [286]

Answer:

b

Step-by-step explanation:

2×5=10 very simple becausevthe equation is e Wii als 0

5 0
3 years ago
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