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luda_lava [24]
3 years ago
10

please someonw help me with 7(a) please please please please please please please please please please please please please plea

se please please​

Mathematics
2 answers:
adelina 88 [10]3 years ago
6 0

Answer: 2+1/x+3

Step-by-step explanation:

timama [110]3 years ago
6 0
The answer is 2+1/x+3
You might be interested in
Triangle def has vertices d(2,-5) e(6,-1) and f(5,6) verify that def is isosceles
goldfiish [28.3K]
To prove that the given triangle is an isosceles, two of its sides must have equal lengths.

Between D(2,-5) and E(6,-1):
d = √(6 - 2)² + (-1 - ⁻5)² = 4√2

Between E(6,-1) and F(5,6):
d = √(5 - 6)² + (6 - ⁻1)² = 5√2

Between D(2,-5) and F(5,6)
d = √(5 - 2)² + (6 - ⁻5)² = √130

<em>Since there are no equal lengths, the triangle is NOT an isosceles triangle.</em>

The bisector of angle F is a line segment from vertex F to the midpoint of line DE.

Midpoint: x = (2+6)/2 = 4; y = (-5+-1)/2 = -3
The midpoint is at (4,-3).
The equation of the line follows the point-slope formula:
y - y₁ = [(y₂ - y₁)/(x₂ - x₁)](x - x₁)
Substituting using points (5,6) and (4,-3)
y - 6 = [(⁻3 - 6)/(4 - 6)](x - 5)
y - 6 = (9/2)(x - 5)
2(y - 6) = 9(x - 5)
2y - 12 = 9x - 45
<em>2y - 9x = -33 </em>

4 0
3 years ago
A simulation was conducted using 10 fair six-sided dice, where the faces were numbered 1 through 6. respectively. All 10 dice we
kompoz [17]

Answer:

C) a sample distribution of a sample mean with n = 10  

\mu_{{\overline}{X}} = 3.5

and \sigma_{{\overline}{Y}} = 0.38

Step-by-step explanation:

Here, the random experiment is rolling 10, 6 faced (with faces numbered from 1 to 6) fair dice and recording the average of the numbers which comes up and the experiment is repeated 20 times.So, here sample size, n = 20 .

Let,

X_{ij} = The number which comes up  on the ith die on the jth trial.

∀ i = 1(1)10 and j = 1(1)20

Then,

E(X_{ij}) = \frac {1 + 2 + 3 + 4 + 5 + 6}{6}

                            = 3.5       ∀ i = 1(1)10 and j = 1(1)20

and,

E(X^{2}_{ij} = \frac {1^{2} + 2^{2} + 3^{2} + 4^{2} + 5^{2} + 6^{2}}{6}

                                = \frac {1 + 4 + 9 + 16 + 25 + 36}{6}

                                = \frac {91}{6}

                                \simeq 15.166667

so, Var(X_{ij} = (E(X^{2}_{ij} - {(E(X_{ij})}^{2})

                                    \simeq 15.166667 - 3.5^{2}

                                    = 2.91667

   and \sigma_{X_{ij}} = \sqrt {2.91667}[/tex                                            [tex]\simeq 1.7078261036

Now we get that,

 Y_{j} = \frac {\sum_{j = 1}^{20}X_{ij}}{20}

We get that Y_{j}'s are iid RV's ∀ j = 1(1)20

Let, {\overline}{Y} = \frac {\sum_{j = 1}^{20}Y_{j}}{20}

      So, we get that E({\overline}{Y}) = E(Y_{j})

                                                                 = E(X_{ij}  for any i = 1(1)10

                                                                 = 3.5

and,

       \sigma_{({\overline}{Y})} = \frac {\sigma_{Y_{j}}}{\sqrt {20}}                                             = \frac {\sigma_{X_{ij}}}{\sqrt {20}}                                             = \frac {1.7078261036}{\sqrt {20}}                                            [tex]\simeq 0.38

Hence, the option which best describes the distribution being simulated is given by,

C) a sample distribution of a sample mean with n = 10  

\mu_{{\overline}{X}} = 3.5

and \sigma_{{\overline}{Y}} = 0.38

                                   

6 0
3 years ago
A recent survey by the cancer society has shown that the probability that someone is a smoker is P(S)=0.29. They have also deter
GuDViN [60]

<u>Answer:</u>

The correct answer option is P (S∩LC) = 0.16.

<u>Step-by-step explanation:</u>

It is known that the probability if someone is a smoker is P(S)=0.29 and the probability that someone has lung cancer, given that they are also smoker is P(LC|S)=0.552.

So using the above information, we are to find the probability hat a random person is a smoker and has lung cancer P(S∩LC).

P (LC|S) = P (S∩LC) / P (S)

Substituting the given values to get:

0.552 = P(S∩LC) / 0.29

P (S∩LC) = 0.552 × 0.29 = 0.16

5 0
3 years ago
Walden’s family is shopping for a reclining chair. The chair the family decided on has a retail price of $800 plus 5% sales tax
Marianna [84]

Answer:

B 10% off sale, with a total price to pay of 756

Step-by-step explanation:

Retail price (Rp) = $800

Taxes (T) = 5%

  • Offer A $75 instant rebate

Total price A (TA) = Rp - 75 + (Rp - 75) 5%

TA = 800 - 75 + (800-75) 5%

TA = 725 + 725 5%

725 5% = 725*5/100 = 36.25

TA= 725+36.25 = $761.25

  • Offer B 10% off sale

Total price B (TB) = RP - RP 10% + (RP - RP 10%) 5%

TB = 800 - 800 10% + (800 - 800 10%) 5%

800 10% = 800*10/100 = 80

TB = 800 - 80 + (800 - 80) 5%

TB = 720 + 720 5%

720 5% = 720*5/100 = 36

TB = 720 + 36 = $756

  • Offer C 5% off sale plus store pays sales tax

store pays sales tax means Walden's family will not need pay for taxes

Total price C (TC) = RP - RP 5%

TC = 800 - 800 5%

800 5% = 800*5/100 = 40

TC = 800 - 40 = $760

  • Offer D a “no tax” sale—the store pays the tax

Means that Walden's family will need pay just the retail price

TD = $800

The beast deal is from the store B

7 0
3 years ago
Read 2 more answers
Is this rational or irrational I really need help ASAP! Will mark brainlist.
vichka [17]

Answer: Rational

A rational number is, as the name implies, any number that can be expressed as a ratio, or fraction. ... 4.5 is a rational number, as it can be represented as 9/2.

I hope this is good enough:

4 0
3 years ago
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