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IrinaVladis [17]
3 years ago
6

How do you workout 7x-19<16

Mathematics
1 answer:
laila [671]3 years ago
7 0

Answer:

To work this problem out you would do it as if it were just a simple equation

7x-19<16 (you would first have to add 19 to both sides)

7x<35 (then you would divide by 7 to get the variable by itself)

x<5 ( you answer would then be 5)

Step-by-step explanation:

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Martin uses 5/8 of a gallon of paint to cover 4/5 of a wall. What is the unit rate at which Martin paints in walls per gallon?
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You can easily solve this by setting up a proportion with walls on the top and paint on the bottom.  First we can find the decimal equivalent of each of those fractions to make things easier.  5/8 = .625 and 4/5 = .8.  \frac{w}{p} : \frac{.8}{.625}= \frac{x}{1}.  What this is asking is "if 4/5 (.8) of a wall is covered by 5/8 (.625) of a gallon of paint, how many walls (x) will 1 gallon of paint cover?"  If we cross multiply we have .625x = .8 and x = 1.28 which is the same as 1 7/25 walls/1 gallon, choice C.
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I’m confused on this one
andrew-mc [135]

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Our equation should then look like after plugged in as....

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An acute triangle has sides measuring 10 cm and 16 cm. The length of the third side is unknown.
saveliy_v [14]

Answer: Choice B

12.5 < x < 18.9

================================================

Explanation:

We have a triangle with these side lengths:

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  • b = 16
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Let's assume that b = 16 is the largest side of this triangle.

By the converse of the pythagorean theorem, we need b^2 < a^2+c^2 to be true in order for an acute triangle to happen.

So,

b^2 < a^2 + c^2\\\\c^2 > b^2 - a^2\\\\c > \sqrt{b^2-a^2}\\\\x > \sqrt{16^2-10^2}\\\\x > \sqrt{156}\\\\x > 12.4899959967968 \ \text{(approximate)}\\\\x > 12.5

Now let's consider the possibility that the missing side x is actually the longest side.

Using the same theorem as before, we would say,

c^2 < a^2 + b^2\\\\c < \sqrt{a^2 + b^2}\\\\x < \sqrt{10^2 + 16^2}\\\\x < \sqrt{356}\\\\x < 18.8679622641132 \ \text{(approximate)}\\\\x < 18.9\\\\

We found that x > 12.5 and x < 18.9

This is the same as saying 12.5 < x and x < 18.9

Put together, they form the approximate answer of 12.5 < x < 18.9

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Answer:

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