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3 years ago

I need answer ASAP I’m next 10 mins

Mathematics

2 answers:

34kurt3 years ago

6 0

Answer:

Step-by-step explanation:

First simplify the first term to get

10y^4

then multiply 10y^4 by 4 square root 6y^3

40y would be all you needed to get answer

Licemer1 [7]3 years ago

5 0

Answer:

40y^5√6y (B)

Step-by-step explanation:

Let's multiply 2√25y^8 * 4√6y^3:

8√150y^11 (When you multiply exponents with the same base, you can just add the exponents and keep the same base:

Ex. 4^5 * 4^9 = 4^14)

Let's simplify 8√150y^11

√150 = 5√6

√y^11 = y^5√y

So our final answer would be:

40y^5√6y

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Seven times a number is 5600. what is the number?

Vika [28.1K]

To do this you need to work backwards. if you note the number as 'n' you can put
7n = 5600
to find n you simply divide both sides by 7 getting
n = 5600/7
n = 800

5 0

3 years ago

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If D is the midpoint of CE, CD= 9x-7, and DE= 3x+17, find CE

tatuchka [14]

Hello!

Since D is the midpoint and the two equations are and both sides of point D the equations equal each other

9x - 7 = 3x + 17

Now you solve it algebraically

Add 7 to both sides

9x = 3x + 24

Subtract 3x from both sides

6x = 24

Divide both sides by 6

x = 4

Now we put this into both equations and add them

9(4) - 7 = 29
3(4) + 17 = 29

29 + 29 = 58

The answer is 58 units

Hope this helps!

3 0

2 years ago

Triangles abc, dbe, and fbg are all symmetric about the y-axis. what are the coordinates of the centroid?

Drupady [299]

Answer:

The coordinates of the centroid are (0, 5)

Step-by-step explanation:

The coordinates of the centroid of a triangle whose vertices (x1, y1), (x2, y2), and (x3, y3) are ( $\frac{x1+x2+x3}{3}$ , $\frac{y1+y2+y3}{3}$ )

In Δ ABC

∵ A = (-20, 0), B = (0, 15), C = (20, 0)

∴ x1 = -20, x2 = 0, x3 = 20

∴ y1 = 0, y2 = 15, y3 = 0

∴ The centroid = ( $\frac{-20+0+20}{3}$ , $\frac{0+15+0}{3}$ ) = ( $\frac{0}{3}$ , $\frac{15}{3}$ ) = (0, 5)

∴ The coordinates of the centroid of Δ ABC are (0, 5)

In Δ DBE

∵ D = (-15, 0), B = (0, 15), E = (15, 0)

∴ x1 = -15, x2 = 0, x3 = 15

∴ y1 = 0, y2 = 15, y3 = 0

∴ The centroid = ( $\frac{-15+0+15}{3}$ , $\frac{0+15+0}{3}$ ) = ( $\frac{0}{3}$ , $\frac{15}{3}$ ) = (0, 5)

∴ The coordinates of the centroid of Δ DBE are (0, 5)

In Δ FBG

∵ F = (-5, 0), B = (0, 15), G = (5, 0)

∴ x1 = -5, x2 = 0, x3 = 5

∴ y1 = 0, y2 = 15, y3 = 0

∴ The centroid = ( $\frac{-5+0+5}{3}$ , $\frac{0+15+0}{3}$ ) = ( $\frac{0}{3}$ , $\frac{15}{3}$ ) = (0, 5)

∴ The coordinates of the centroid of Δ FBG are (0, 5)

∵ The three triangles are symmetric about the y-axis

→ That means they have the same centroid and it lies on the y-axis

∴ The coordinates of the centroid are (0, 5)

8 0

2 years ago

The velocity of an automobile starting from rest is given by the equation below, where v is measured in feet per second and t is

podryga [215]

Answer:

(a) $0.408m/sec^2$

(b) $0.134m/sec^2$

Step-by-step explanation:

We have given velocity as function of t $v(t)=\frac{85t}{(8t+14)}$

Acceleration is equation rate if change of velocity with respect to time

So $a=\frac{dv}{dt}=\frac{(8t+14)85-85t\times 8}{(8t+14)^2}$

(a) Acceleration at t = 5 sec

$a=\frac{(8\times 5+14)85-85\times 5\times 8}{(8\times 5+14)^2}=0.408m/sec^2$

(b) Acceleration at t = 10 sec

$a=\frac{(8\times 10+14)85-85\times 10\times 8}{(8\times 10+14)^2}=0.134m/sec^2$

$a=\frac{(8\times 20+14)85-85\times 20\times 8}{(8\times 20+14)^2}=0.039m/sec^2$

5 0

3 years ago

Please help me with this

Art [367]

Answer:

the mean is 5

Step-by-step explanation:

because if you add all the numbers and divide by the number of digits you should get the equation 40/8= 5 and that´s the answer

6 0

2 years ago

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