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2 answers:
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The complete question in the attached figure
we know that
the diagonals of a rhombus intersect to form right angles,
so
angle ACE is ----------> (90°-64°)-----------> 26°
ACE is the angle bisector of ACD, this means that ACD is ---------> 26 x 2 = 52°
The diagonals are angle bisectors to the opposite corners
so
ACD = ACB = 52°
and
BCD = 52 x 2 = 104°
For a rhombus, opposite angles are equivalent,
so
BAD = BCD = 104°
the answer is
angle BAD=104°
we know that
the diagonals of a rhombus intersect to form right angles,
so
angle ACE is ----------> (90°-64°)-----------> 26°
ACE is the angle bisector of ACD, this means that ACD is ---------> 26 x 2 = 52°
The diagonals are angle bisectors to the opposite corners
so
ACD = ACB = 52°
and
BCD = 52 x 2 = 104°
For a rhombus, opposite angles are equivalent,
so
BAD = BCD = 104°
the answer is
angle BAD=104°
Answer:
sinФ = 8/17
cosФ = 15/17
tan Ф = 8/15
csc Ф = 17/8
sec Ф = 17/15
cot Ф = 15/8
Step-by-step explanation:
Let us revise the trigonometry functions
- Sin(x) = opposite/hypotenuse
- Cos(x) = adjacent/hypoteouse
- Tan(x) = opposite/adjacent
- Csc(x) = hypotenuse/opposit
- Sec(x) = hypotenues/adjacent
- Cot(x) = adjacent/opposite
In the given figure
The opposite side to angle Ф = 8
The adjacent side to angle Ф = 15
Find the hypotenuse using Pythagoras' theorem
Let us use the rules above to find the trigonometry functions
sinФ = 8/17
cosФ = 15/17
tan Ф = 8/15
csc Ф = 17/8
sec Ф = 17/15
cot Ф = 15/8
Answer:
Step-by-step explanation:
refer to solution in the picture
