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vazorg [7]
3 years ago
15

What goes in the green box and what is 6 * 28 ​

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
7 0
6*28= 168
You put 168 in the green box
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There are 25 trees on the Jackson’s property. Twenty percent of the trees are oak trees. Which equation can be used to find the
ahrayia [7]

Answer:

StartFraction 25 divided by 1 Over 20 divided by 1 EndFraction = StartFraction 25 Over 20 EndFraction

Step-by-step explanation:

Number of trees = 25

Percentage of aok trees = 20%

To obtain the Number of oak trees :

(Number of trees ÷ 1) ÷ (percentage ÷1)

(25 / 1) ÷ (20 / 1) = (25 /1) * (20 / 1) = 25 / 20

StartFraction 25 divided by 1 Over 20 divided by 1 EndFraction = StartFraction 25 Over 20 EndFraction

8 0
2 years ago
Jill had some candy to give to her five
Mama L [17]
She started with 32 pieces.

Explanation: If she had 5 children and each child received 5 pieces, you can determine that she gave her children a total of 25 pieces because 5 x 5 = 25. If she took 7 pieces for herself before giving the rest away, you can determine that she had 32 pieces of candy to start with because 25 + 7 = 32.
8 0
2 years ago
Write the ratio 28 inches to 5 feet as a fraction in simplest form
Schach [20]
5 feet is 5*12=60 inches.  Therefore, our ratio is 28:60. Dividing both terms by 4, we see that the most simple ratio is 7:15.
6 0
3 years ago
There are two college entrance exams that are often taken by students, Exam A and Exam B. The composite score on Exam A is appro
elena55 [62]

Answer:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Two exams. The exam that you did score better is the one in which you had a higher zscore.

The composite score on Exam A is approximately normally distributed with mean 20.1 and standard deviation 5.1.

This means that \mu = 20.1, \sigma = 5.1.

You scored 24 on Exam A. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{24 - 20.1}{5.1}

Z = 0.76

The composite score on Exam B is approximately normally distributed with mean 1031 and standard deviation 215.

This means that \mu = 1031, \sigma = 215.

You scored 1167 on Exam B, s:

Z = \frac{X - \mu}{\sigma}

Z = \frac{1167 - 1031}{215}

Z = 0.632

You had a better Z-score on exam A, so you did better on that exam.

The correct answer is:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

3 0
3 years ago
How to convert 80 kilometers per hour is 60 miles per hour?
Tatiana [17]
1 km = 0.62 mi
1 mi = 1.6 km

80*0.62
  -or-
60*1.6

Hope this helps
5 0
2 years ago
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