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Irina-Kira [14]
3 years ago
8

At Smith’s Bike Rentals, it cost $27 to rent a bike for 6 hours. How many dollars does it cost per hour of bike use

Mathematics
2 answers:
lilavasa [31]3 years ago
8 0

Answer:

$4.50 per hour

Step-by-step explanation:

Step 1: 27 divided by 6 is 4.50

Step 2: Double check your work by multiplying 4.50 times 6 to make sure you get 27

Delicious77 [7]3 years ago
5 0
To find how much it would cost for one hour you would need to divide 27 by 6.

27/6 = 4.5

Therefore it costs $4.5 to rent the bike per hour
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OlgaM077 [116]
Scale factor is a ratio, you have to remember that. divide the lengths and you will see a constant cratio

5 0
3 years ago
F(x) 5x/x-2
Phoenix [80]

Answer:

Vertical asymptote: x=2

Horizontal asymptote: y=5

Step-by-step explanation:

Hi there!

The parent function for a rational function has a horizontal asymptote at y=0 and a vertical asymptote at x=0.

First, we want to perform long division on 5x/x-2. Please check the image attached.

The result is 5+\displaystyle\frac{10}{x-2}.

Here are the transformations of a rational function:

f(x)=\displaystyle\frac{a}{b(x-h)}+k

a = vertical stretch

b = horizontal stretch

h = horizontal translation

k = vertical translation

Stretches don't change the location of the asymptotes, only the translations do.

According to 5+\displaystyle\frac{10}{x-2}, we applied a horizontal translation of 2 units right and a vertical translation of 5 units up. Therefore, our asymptotes are now x=2 and y=5.

I hope this helps!

6 0
2 years ago
What is the antiderivative of sin^2(x)cos^2(x)?
marin [14]

Answer:

\frac{x}{8}-\frac{\sin(4x)}{32}+C

Step-by-step explanation:

[Most of the work here comes from manipulating the trig to make the term (integrand) integrable.]

Recall that we can express the squared trig functions in terms of cos(2x). That is,

\cos(2x)=2\cos^2x-1 \\ \cos(2x)=1 - 2\sin^2x.

And so inverting these,

\cos^2x=\frac{1}{2} (1+\cos2x) \\ \sin^2x=\frac{1}{2} (1-\cos2x).

Multiply them together to obtain an equivalent expression for sin^2(x)cos^2(x) in terms of cos(2x).

\sin^2x \cdot \cos^2x =\frac{1}{2} (1-\cos2x) \cdot \frac{1}{2} (1+\cos2x) = \frac{1}{4}(1-\cos^2(2x)).

Notice we have cos^2(2x) in the integrand now. We've made it worse! Let's try plugging back in to the first identity for cos^2(2x).

\cos(2x)=2\cos^2x-1 \Rightarrow \cos(4x)=2\cos^2(2x)-1 \Rightarrow \cos^2(2x) = \frac{1}{2}(1+\cos(4x))

So then,

\sin^2x \cdot \cos^2x = \frac{1}{4}(1-\cos^2(2x)) = \frac{1}{4}(1-\frac{1}{2}(1+\cos(4x))) = \frac{1}{4}(1-\frac{1}{2}-\frac{1}{2}\cos(4x))=\frac{1}{8}(1-\cos(4x)).

This is now integrable (phew),

\int \sin^2x\cos^2x \ dx = \int \frac{1}{8}(1-\cos(4x)) \ dx = \frac{1}{8} \int (1-\cos(4x)) \ dx = \frac{1}{8}(x-\frac{1}{4}\sin(4x))+C.

7 0
3 years ago
Help me please I really do need help tho
Mekhanik [1.2K]

Answer: What musickp8809 said

Step-by-step explanation: Give him brainliest, bc that's what i want for christmas.

6 0
3 years ago
PLZ HELP IF RIGHT THEN YOU'LL GET BRAINLIEST
Dmitry [639]

Answer:

2% decrease

Step-by-step explanation:

Steps to find percent decrease:

- Subtract starting value minus final value

- Divide that amount by the absolute value of the starting value

- Multiply by 100 to get percent decrease

4 0
3 years ago
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