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Law Incorporation [45]
3 years ago
8

Sam created a porch that was part wooden and part concrete, as shown in the figure below. Note: Figure not drawn to scale If a =

21 ft, b = 28 ft, and c = 35 ft, what is the total area of the porch? Assume that the wooden part is a right triangle and the concrete part is a square. A. 1,519 ft2 B. 1,715 ft2 C. 217 ft2 D. 119 ft2
Mathematics
1 answer:
rjkz [21]3 years ago
3 0
Youre gonna have to upload a picture of the porch, "figure below"
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Can someone help me, please? Also, can someone explain it?
Arada [10]

Answer:60m^2

Step-by-step explanation:you have to find the height of the triangle first which is easy bc it’s been split in half so the are now two right triangles. use the pythagorean theorem to determine the height, the height is 12, the formula for the area of a triangle is 1/2bxa and half of the base is already given to you, 5 so 5 x 12 equals 60

5 0
3 years ago
What transformation was made for this triangle?
Musya8 [376]

Answer:

Dilation

Step-by-step explanation:

Dilation is when a shape is made bigger but the form of the shape does not change. So its enlarged.

7 0
3 years ago
you are building a rectangular wading pool you want the area of the bottom to be 90 ft squared you want the length of the pool t
Sindrei [870]
L=2W+3, A=LW, using L from the first in the second gives you:

A=(2W+3)W

A=2W^2+3W, and we are told A=90 so

2W^2+3W=90

2W^2+3W-90=0

2W^2-12W+15W-90=0

2W(W-6)+15(W-6)=0

(2W+15)(W-6)=0, since W>0 for all real possibilities, 

W=6ft, and since L=2W+3

L=15ft

So the pool will be 6 ft wide by 15 ft long.
5 0
3 years ago
X is greater than or equal to -1 and less than or equal to 8
Sergeeva-Olga [200]

Answer:

Is their an equation that can be used a reference to find the sum/difference/product/quotient to this equation?

Step-by-step explanation:

4 0
3 years ago
What is the graph of the solution to the following compound inequality?
ohaa [14]

Answer:

<h2>C.</h2>

Step-by-step explanation:

<, > - open circle

≤, ≥ - solid circle

<, ≤ - draw to the left

>, ≥ - draw to the right

3-x\geq2\qquad\text{subtract 3 from both sides}\\\\-x\geq-1\qquad\text{change the signs}\\\\\boxed{x\leq1}\\\\4x+2\geq10\qquad\text{subtract 2 from both sides}\\\\4x\geq8\qquad\text{divide both sides by 4}\\\\\boxed{x\geq2}

3 0
4 years ago
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