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morpeh [17]
2 years ago
9

How to slove 3/5(2.4)

Mathematics
2 answers:
yanalaym [24]2 years ago
6 0
3/5 * 2.4 = 0.6 *2.4 =1.44
Oduvanchick [21]2 years ago
3 0
3 / 5 * 2.4 = 0.6 * 2.4 = 1.44
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Determine if each function is linear or nonlinear.
olga nikolaevna [1]

Answer:

To see if a table of values represents a linear function, check to see if there's a constant rate of change. If there is, you're looking at a linear function!


Step-by-step explanation:


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A package being delivered in the mail weighs 1056 ounces. How much does that package weigh in pounds?
Vlad1618 [11]

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66

Step-by-step explanation:

16 oz equal a pound so 1056 divided by 16

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Can someone give me the answers for theses I’ve been lost all day with online school
lilavasa [31]

Answer:

True. That is a function.

Step-by-step explanation:

A function just means that every input has only one output. The simpler way to do these is the vertical line test. Draw a vertical line anywhere on the graph and see if the vertical line is intersected in two places. If the vertical line is crossed twice, the graph isn't a function.

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2 years ago
What is the length of the hypotenuse of the right triangle shown below? If necessary, round your answer to the nearest hundredth
kolezko [41]
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8 0
3 years ago
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An apartment complex rents an average of 2.3 new units per week. If the number of apartment rented each week Poisson distributed
masya89 [10]

Answer:

P(X\leq 1) = 0.331

Step-by-step explanation:

Given

Poisson Distribution;

Average rent in a week = 2.3

Required

Determine the probability of renting no more than 1 apartment

A Poisson distribution is given as;

P(X = x) = \frac{y^xe^{-y}}{x!}

Where y represents λ (average)

y = 2.3

<em>Probability of renting no more than 1 apartment = Probability of renting no apartment + Probability of renting 1 apartment</em>

<em />

Using probability notations;

P(X\leq 1) = P(X=0) + P(X =1)

Solving for P(X = 0) [substitute 0 for x and 2.3 for y]

P(X = 0) = \frac{2.3^0 * e^{-2.3}}{0!}

P(X = 0) = \frac{1 * e^{-2.3}}{1}

P(X = 0) = e^{-2.3}

P(X = 0) = 0.10025884372

Solving for P(X = 1) [substitute 1 for x and 2.3 for y]

P(X = 1) = \frac{2.3^1 * e^{-2.3}}{1!}

P(X = 1) = \frac{2.3 * e^{-2.3}}{1}

P(X = 1) =2.3 * e^{-2.3}

P(X = 1) = 2.3 * 0.10025884372

P(X = 1) = 0.23059534055

P(X\leq 1) = P(X=0) + P(X =1)

P(X\leq 1) = 0.10025884372 + 0.23059534055

P(X\leq 1) = 0.33085418427

P(X\leq 1) = 0.331

Hence, the required probability is 0.331

6 0
2 years ago
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