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vivado [14]
3 years ago
15

What is the length of AC?

Mathematics
2 answers:
MatroZZZ [7]3 years ago
8 0
The sin <ABC means that AC/AB. So we know AB=34. AC/AB=8/17. So the length of AC is 16. cos<ABC means BC/AB. tan<ABC means AC/BC.
algol [13]3 years ago
5 0
We have that
AB=34
sin ∠ABC=\frac{8}{17}

we know that
in the right triangle ABC
sin ∠ABC is equal to  \frac{AC}{AB}
AC is the opposite side angle B
AB is the Hypotenuse

sin ∠ABC=\frac{8}{17}  equation 1

sin ∠ABC=\frac{AC}{34}  equation 2

equate equation 1 and equation 2

\frac{8}{17}  = \frac{AC}{34}  \\  \\ AC=34* \frac{8}{17} \\  \\ AC=16

the answer is
AC=16

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(6 + 3) = (4-5) = 18<br> Evaluate the following numerical expressions
Leya [2.2K]

Answer:

the answer to this question is 18....to complete this you have to multiple first then add

(Sorry.. im kind of confused by this question...

5 0
3 years ago
Help plz:))) I’ll mark u brainliest
egoroff_w [7]

Answer:

Im pretty sure it is c

Step-by-step explanation:

it gives us 2 angles add up to 180, but they are right next to each other. So we cant determine parallel lines.

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6 0
3 years ago
A bag contains white marbles and green marbles, 62 in total. The number of white marbles is 3 less than 4 times the number of gr
Sedaia [141]

Answer:

There are 49 white marbles.

Step-by-step explanation:

w + g = 62        (w = white and g = green marbles).

w = 4g - 3

w - 4g = -3        Subtract this equation from the first equation:

g - (-4g) =  62 - (-3)

5g = 65

g = 65/5 = 13.

So w = 62 - 13 = 49.

3 0
3 years ago
I need help<br> please and thank you
REY [17]
I believe it’s
D.51is it B ??
7 0
3 years ago
What is the determinant of the coefficient matrix of this system? <br> 4x-3y=-8 <br> 8x-3y=12
gladu [14]

The coefficient matrix is build with its rows representing each equation, and its columns representing each variable.

So, you may write the matrix as

\left[\begin{array}{cc}\text{x-coefficient, 1st equation}&\text{y-coefficient, 1st equation}\\\text{x-coefficient, 2nd equation}&\text{y-coefficient, 2nd equation} \end{array}\right]

which means

\left[\begin{array}{cc}4&-3\\8&-3\end{array}\right]

The determinant is computed subtracting diagonals:

\left | \left[ \begin{array}{cc}a&b\\c&d\end{array}\right]\right | = ad-bc

So, we have

\left | \left[\begin{array}{cc}4&-3\\8&-3\end{array}\right] \right | = 4(-3) - 8(-3) = -4(-3) = 12

8 0
3 years ago
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