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lapo4ka [179]
3 years ago
15

Can someone please help me , I really need it

Mathematics
1 answer:
Nikitich [7]3 years ago
6 0
((1/3 + 1)/(3))/(4)
((1/3 + 1)/(3))/(4) = (1/3 + 1)/(3×4):
(1/3 + 1)/(3×4)
Put 1 + 1/3 over the common denominator 3. 1 + 1/3 = 3/3 + 1/3:
(3/3 + 1/3)/(3×4)
3/3 + 1/3 = (3 + 1)/3:
((3 + 1)/3)/(3×4)
3 + 1 = 4:
(4/3)/(3×4)
4/(3×3×4) = 4/(3×4×3):
4/(3×4×3)
4/(3×4×3) = 4/4×1/(3×3) = 1/(3×3):
1/(3×3)
3×3 = 9:
Answer:  1/9 gallons of yellow paint

((1/4 + 1)/(4))/(3)
Put 1 + 1/4 over the common denominator 4. 1 + 1/4 = 4/4 + 1/4:
((4/4 + 1/4)/(4))/(3)
4/4 + 1/4 = (4 + 1)/4:
(((4 + 1)/4)/(4))/(3)
4 + 1 = 5:
((5/4)/4)/3
4×4 = 16:
5/(16×3)
16×3 = 48:
Answer:  5/48  Gallons of green paint

(7/3×1/4)/8
(7/3×1/4)/8 = 7/(3×4×8):
7/(3×4×8)
3×4 = 12:
7/(12×8)
12×8 = 96:
<span>Answer:  7/96 Gallons of blue paint

Combine:

1/9 + 5/48 + 7/96
Put 1/9 + 5/48 + 7/96 over the common denominator 288. 1/9 + 5/48 + 7/96 = 32/288 + (6×5)/288 + (3×7)/288:
32/288 + (6×5)/288 + (3×7)/288
6×5 = 30:
32/288 + 30/288 + (3×7)/288
3×7 = 21:
32/288 + 30/288 + 21/288
32/288 + 30/288 + 21/288 = (32 + 30 + 21)/288:
(32 + 30 + 21)/288
 | 3 | 2
 | 3 | 0
+ | 2 | 1
 | 8 | 3:<span>Answer:  83/288  or </span><span>0.2881944... </span>Gallons are left over</span>

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5 0
4 years ago
The tanks at the Georgia Aquarium hold approximately 8.4 x 10⁶ gallons of water. The tanks at the Audubon Aquarium of the Americ
postnew [5]

The amount of water at the Georgia Aquarium is 2 * 10¹ times greater than the aquarium of the Americas hold.

<h3>How to work with scientific notation of numbers?</h3>

Scientific notation is a way of writing very large or very small numbers. A number is written in scientific notation when a number between 1 and 10 is multiplied by a power of 10.

We are given that the tanks at the Georgia Aquarium hold approximately 8.4 × 10⁶ gallons of water.

Meanwhile, the tanks at the Audubon Aquarium of the Americas hold about 400,000 gallons of water.

Thus, to estimate how many times as great the amount of water is at the Georgia Aquarium, we will divide as;

(8.4 × 10⁶)/(400000)

Converting 8.4 × 10⁶ to normal number gives;

8400000

Thus;

(8.4 × 10⁶)/(400000) = 8400000/400000

= 21

Thus, writing in scientific notation gives;

2.1 * 10¹ approximately 2 * 10¹

Read more about Scientific Notation at; brainly.com/question/27862246

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6 0
1 year ago
Find the Midpoint of CD?
Hatshy [7]

Add the x-coordinates and divide by 2.

Add the y-coordinates and divide by 2.

x-coordinate of midpoint: (-3 + 5)/2 = 2/2 = 1

y-coordinate of midpoint: (4 - 8)/2 = -4/2 = -2

Answer: (1, -2)

4 0
3 years ago
PLEASE HELP WITH THIS QUESTION​
Vanyuwa [196]

Answer:

A

Step-by-step explanation:

2x < 8

x < 8/2

x < 4

The sign stays in the same direction since you are dividing by positive.  The circle is not filled in because x is NOT less than or equal to 4.

5 0
3 years ago
Engineers want to design seats in commercial aircraft so that they are wide enough to fit ​99% of all males.​ (Accommodating 100
Nezavi [6.7K]

Answer:

p99 = 16.4 inches

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Men have hip breadths that are normally distributed with a mean of 14.3 in. And a standard deviation of 0.9 in.

This means that \mu = 14.3, \sigma = 0.9

Find p99.

This is the value of X when Z has a p-value of 0.99, so X when Z = 2.327. Then

Z = \frac{X - \mu}{\sigma}

2.327 = \frac{X - 14.3}{0.9}

X - 14.3 = 0.9*2.327

X = 16.4

So

p99 = 16.4 inches

8 0
3 years ago
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