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Aleks04 [339]
4 years ago
8

Draw the graph of relation defined by Y^2=3x

Mathematics
1 answer:
Alexeev081 [22]4 years ago
3 0
This is the graph and I will include some properties

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Find the equation of the line. <br> Use exact numbers.
AlekseyPX
The slope of the line (m) = 3/1  = 3  
and the y intercept is at (0,3)  that is y = 3  so b = 3

using the slope intercept form y = mx + b

m = 3 and b = 3

so answer is y = 3x + 3
8 0
4 years ago
Read 2 more answers
300-297+294-291+288-285+...+6-3
vladimir2022 [97]
300 - 297 = 3

294 - 291 = 3

288 - 285 = 3

So, that is a sequence of sums of number 3: 3 + 3 + 3 + .... + 3

How may times will the number 3 be added?

Note that 300 is reduced in 6 units each time => 300 / 6 = 50 => 3 will be added 50 times.

=> 50 * 3 = 150

Answer: 150
7 0
3 years ago
What is the value of y−5x−3for x = 2 and y = -4
arlik [135]

Answer

-17


<u>Explanation</u>

y−5x−3 for x = 2 and y = -4

We solve this question by substituting the values of y and x.

y−5x−3 = -4 - 5(2) - 3

             = -4 - 10 -3

             = -14 - 3

            = -17

8 0
4 years ago
Read 2 more answers
What is the area of a sector that has a radius of 25 mm and has an angle measure of 50
attashe74 [19]

Answer : The area of sector is, 272.57mm^2

Step-by-step explanation :

Formula used to calculate the area of sector in degree is:

Area of sector = \frac{\theta}{360}\pi r^2

where,

\theta = angle = 50^o

r = radius = 25 mm

Now put all the given values in the above formula, we get:

Area of sector = \frac{\theta}{360}\pi r^2

Area of sector = \frac{50}{360}\times 3.14\times (25)^2

Area of sector = 272.57mm^2

Therefore, the area of sector is, 272.57mm^2

7 0
3 years ago
Can someone help me with this math homework please!
blondinia [14]

Answer:

C

Step-by-step explanation:

y coordinates must be at the numerator, while x coordinates at the denominator

4 0
3 years ago
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