Step-by-step explanation:
Given function is,
Where,
y = amount paid to the gym in dollars
x = number of months
So when x = 0, y =55(0)+80 = 80
i.e when number of months is 0, you have to pay a fee of $80.
This is the one time fee to open a membership.
After that for each month you have to pay $55 for each months.
So 55 is multiplied with x.
Answer:
g(x) = sinh^-1 ( ln(7x^6 +3) / sqrt( 8+cot( x^( 3+x))))
Step-by-step explanation:
Using the fundamental theorem of calculus
Taking the derivative of the integral gives back the function
Since the lower limit is a constant when we take the derivative it is zero
d/dx
g(t) = sinh^-1 ( ln(7t^6 +3) / sqrt( 8+cot( t^( 3+t))))
Replacing t with x
g(x) = sinh^-1 ( ln(7x^6 +3) / sqrt( 8+cot( x^( 3+x))))
Answer:
$36 400
Step-by-step explanation:
Step 1
The first step is to figure out how much money is saved at the end of each month for the period from January 1 to June 15. The amount deposited at the end of each month is obtained by multiplying the amount from the previous month by 3.
The amount deposited in January is
The amount deposited in February is
The amount deposited in March is
The amount deposited in April is
The amount deposited in May is
The amount deposited in June is
Step 2
The next step is to add up all the money that was deposited into the account. This calculation is shown below,
