Solution set is: (
)
Option B is correct
Step-by-step explanation:
We need to find the solution to system of equations
![y=\frac{1}{3}x+2\\y=\frac{4}{3}x-5](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B1%7D%7B3%7Dx%2B2%5C%5Cy%3D%5Cfrac%7B4%7D%7B3%7Dx-5)
Let:
![y=\frac{1}{3}x+2\,\,\,eq(1)\\y=\frac{4}{3}x-5\,\,\,eq(2)](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B1%7D%7B3%7Dx%2B2%5C%2C%5C%2C%5C%2Ceq%281%29%5C%5Cy%3D%5Cfrac%7B4%7D%7B3%7Dx-5%5C%2C%5C%2C%5C%2Ceq%282%29)
Putting value of y from eq(2) into eq(1)
![\frac{4}{3}x-5=\frac{1}{3}x+2\\Combining\,\,like\,\,terms:\\\frac{4}{3}x-\frac{1}{3}x=2+5\\Taking\,\,LCM\\\frac{4x-1x}{3}=7\\\frac{3x}{3}=7\\x=7](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B3%7Dx-5%3D%5Cfrac%7B1%7D%7B3%7Dx%2B2%5C%5CCombining%5C%2C%5C%2Clike%5C%2C%5C%2Cterms%3A%5C%5C%5Cfrac%7B4%7D%7B3%7Dx-%5Cfrac%7B1%7D%7B3%7Dx%3D2%2B5%5C%5CTaking%5C%2C%5C%2CLCM%5C%5C%5Cfrac%7B4x-1x%7D%7B3%7D%3D7%5C%5C%5Cfrac%7B3x%7D%7B3%7D%3D7%5C%5Cx%3D7)
So, value of x=7
Putting value of x into equation 1 to find the value of y:
![y=\frac{1}{3}x+2\\y=\frac{1}{3}(7)+2\\y=\frac{7}{3}+2\\Taking\,\,LCM\\y=\frac{7+2*3}{3}\\y=\frac{7+6}{3}\\y=\frac{13}{3}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B1%7D%7B3%7Dx%2B2%5C%5Cy%3D%5Cfrac%7B1%7D%7B3%7D%287%29%2B2%5C%5Cy%3D%5Cfrac%7B7%7D%7B3%7D%2B2%5C%5CTaking%5C%2C%5C%2CLCM%5C%5Cy%3D%5Cfrac%7B7%2B2%2A3%7D%7B3%7D%5C%5Cy%3D%5Cfrac%7B7%2B6%7D%7B3%7D%5C%5Cy%3D%5Cfrac%7B13%7D%7B3%7D)
So, value of y = ![\frac{13}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B13%7D%7B3%7D)
Solution set is: (
)
Option B is correct
Keywords: System of equations
Learn more about system of equations at:
#learnwithBrainly
Answer:
the answer is blurry for me take a picture again
Step-by-step explanation:
Answer:r'=0.327 m
Step-by-step explanation:
Given
![N=2.85 rev/s](https://tex.z-dn.net/?f=N%3D2.85%20rev%2Fs)
angular velocity ![\omega =2\pi N=17.90 rad/s](https://tex.z-dn.net/?f=%5Comega%20%3D2%5Cpi%20N%3D17.90%20rad%2Fs)
mass of objects ![m=1.5 kg](https://tex.z-dn.net/?f=m%3D1.5%20kg)
distance of objects from stool ![r_1=0.789 m](https://tex.z-dn.net/?f=r_1%3D0.789%20m)
Combined moment of inertia of stool and student ![=5.53 kg.m^2](https://tex.z-dn.net/?f=%3D5.53%20kg.m%5E2)
Now student pull off his hands so as to increase its speed to 3.60 rev/s
![\omega _2=2\pi N_2](https://tex.z-dn.net/?f=%5Comega%20_2%3D2%5Cpi%20N_2)
![\omega _2=2\pi 3.6=22.62 rad/s](https://tex.z-dn.net/?f=%5Comega%20_2%3D2%5Cpi%203.6%3D22.62%20rad%2Fs)
Initial moment of inertia of two masses ![I_0=2mr_^2](https://tex.z-dn.net/?f=I_0%3D2mr_%5E2)
![I_0=2\times 1.5\times (0.789)^2=1.867](https://tex.z-dn.net/?f=I_0%3D2%5Ctimes%201.5%5Ctimes%20%280.789%29%5E2%3D1.867)
After Pulling off hands so that r' is the distance of masses from stool
![I_0'=2\times 1.5\times (r')^2](https://tex.z-dn.net/?f=I_0%27%3D2%5Ctimes%201.5%5Ctimes%20%28r%27%29%5E2)
Conserving angular momentum
![I_1\omega =I_2\omega _2](https://tex.z-dn.net/?f=I_1%5Comega%20%3DI_2%5Comega%20_2)
![(5.53+1.867)\cdot 17.90=(5.53+I_o')\cdot 22.62](https://tex.z-dn.net/?f=%285.53%2B1.867%29%5Ccdot%2017.90%3D%285.53%2BI_o%27%29%5Ccdot%2022.62)
![I_0'=1.397\times 0.791](https://tex.z-dn.net/?f=I_0%27%3D1.397%5Ctimes%200.791)
![I_0'=5.851](https://tex.z-dn.net/?f=I_0%27%3D5.851)
![5.53+2\times 1.5\times (r')^2=5.851](https://tex.z-dn.net/?f=5.53%2B2%5Ctimes%201.5%5Ctimes%20%28r%27%29%5E2%3D5.851)
![2\times 1.5\times (r')^2=0.321](https://tex.z-dn.net/?f=2%5Ctimes%201.5%5Ctimes%20%28r%27%29%5E2%3D0.321)
![r'^2=0.107009](https://tex.z-dn.net/?f=r%27%5E2%3D0.107009)
![r'=0.327 m](https://tex.z-dn.net/?f=r%27%3D0.327%20m)
Answer:
Step-by-step explanation:
The complete question is given thus:
Suppose that computer literacy among people ages 40 and older is being studied and that the accompanying tables describes the probability distribution for four randomly selected people, where x is the number that are computer literate. Is it unusual to find four computer literates among four randomly selected people?
x P(x)
0 0.16
1 0.25
2 0.36
3 0.15
4 0.08
ANSWER:
The odds that this will occur according to the chart are 0.08, or 8%, so although this is unlikely, it's not terribly unusual.
⇒ NO
So from the following we can say it is not unusual to find four (4) computer literates among four randomly selected people.
ok, so P(1) + P(2) + P(3) + P(4) + P(0) = 0.16+0.25+0.36+0.15+0.08 = 1
Whereas the chance of finding four (4) out of four (4) computer iteration is low when compared to other factors.
cheers i hope this helped !!
Answer:
6-(6)(6-6) = 6
Step-by-step explanation:
6-6 is 0
6*0 is 0
6-0 is 6
6 is answer