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valkas [14]
3 years ago
7

please solve the question and show your work find the missing number in 34x =0 show how u got your answer and write full explana

tion and tell me why your answer is right
Mathematics
1 answer:
Anastaziya [24]3 years ago
8 0
34x=0
So we need to isolate x. Since 34 is multiplied by x, we need to isolate x by moving 34 over the equal sign. Whenever you move something over the equal sign, the opposite is done. For 34, instead of being multiplied, it will be divided.
34x=0
X=0/34
Then you solve for x
X=0
Hope this helps!
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in a xy-coordinate system line 1 has a slope of -3. If the points (2,16 and (5,t) are on line 1, what is the value of t?
Dimas [21]
We can use the formula y2-y1/x2-x1 to find our answer. So, we have : t-16/5-2 = -3. We simplify that to t-16/3 = -3. We can then multiply both sides by 3 to get t-16 = -9. Then we can add 16 to both sides to get t = 7.
8 0
3 years ago
The sums that appear when two fair? four-sided dice? (tetrahedrons) with sides 1?, 2?, 3?, and 4 are tossed
Karolina [17]

Answer:

The possible sums are 2, 3, 4, 5, 6, 7 & 8 (but they're not all equally likely)

Step-by-step explanation:

For example, the only way to get a sum of 2 is to roll a 1 and then a 1

And the only way to get a sum of 8 is to roll a 4 and then a 4 (imagine you don't roll the two dice simultaneously; this will help you to see the "other possibilities" that aren't obvious at first)

The probability of rolling a sum of 2 = probability of rolling sum of 8 (1/16 probability for each)

If you roll a 1 then a 2, or a 2 then a 1, there are 2 ways to get a sum of 3

If you roll a 3 then a 1, a 2 then a 2, or a 1 then a 3, there are 3 ways to get a sum of 4

If you roll a 4 then a 1, a 3 then a 2, a 2 then a 3, or a 1 then a 4, there are 4 ways to get a sum of 5 (5 is the most likely sum)

If you roll a 4 then a 2, a 3 then a 3, or a 2 then a 4, there are 3 ways to get a sum of 6

If you roll a 4 then a 3, or a 3 then a 4, there are 2 ways to get a sum of 7

5 0
3 years ago
A rectangular parking lot must have a perimeter of 440 feet and an area of at least 8000 square feet. Describe the possible leng
tangare [24]

Answer:

The possible parking lengths are 45.96 feet and 174.031 feet

Step-by-step explanation:

Let x be the length of rectangular plot and y be the breadth of rectangular plot

A rectangular parking lot must have a perimeter of 440 feet

Perimeter of rectangular plot =2(l+b)=2(x+y)=440

2(x+y)=440

x+y=220

y=220-x

We are also given that an area of at least 8000 square feet.

So, xy \leq 8000

So,x(220-x) \leq 8000

220x-x^2 \leq 8000

So,220x-x^2 = 8000\\-x^2+220x-8000=0

General quadratic equation : ax^2+bx+c=0

Formula : x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

x=\frac{-220 \pm \sqrt{220^2-4(-1)(-8000)}}{2(-1)}\\x=\frac{-220 + \sqrt{220^2-4(-1)(-8000)}}{2(-1)} , \frac{-220 - \sqrt{220^2-4(-1)(-8000)}}{2(-1)}\\x=45.96,174.031

So, The possible parking lengths are 45.96 feet and 174.031 feet

3 0
3 years ago
Can you guys help we with this question. ​​​​​​
satela [25.4K]

Answer:

40

Step-by-step explanation:

(2x+1/(2x))^5 *(2x -1/(2x))^5

= ((2x)^2 -1/(2x)^2)^5 (a+b)*(a-b) =a2-b2

= (4x^2-1/4(x)^2)^5

now

x =4x^2. ,a = 1/4(x)^2 ,n =5

we have

general term = Cr *x^r *a^(n-r)

= Cr * (4x^2)^r * (1/4(x)^2)^(n-r)

= Cr *4^r * X^2r * 1/( 4^(n-r) *x^(2n-2r)

= Cr * 4^r/4^(n-r) * x^(2r)/x^(2n-2r)

= Cr * 4(2r-n) *x(4r-2n)

now for x^2

4r-2n = 2

4r -10=2

4r =12

r = 3

now for coeff

C(5,3) * 4^(2*3-5)

5!/(3!*(5-3)!) * 4

5*4/(2*1)*4

40

4 0
3 years ago
Read 2 more answers
-1/2+-5/6 thank you
aleksandrvk [35]

Answer:

-1 1/3 hope this helps

Step-by-step explanation:

8 0
3 years ago
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