Answer:

So then the expected value in the long run for this case would be 19 millions
Step-by-step explanation:
Previous concepts
The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete. And is defined as:

For 
Solution to the problem
Let's define the random variable X as the expected return for a new drug.
For this case we expected a return of X=750 millions with a probability of 0.14. We assume that p is the probability of success for this case p =0.14.
And the probability of no success on this case would be q = 1-p = 1-0.14 =0.86. And the cost associated for this case would be X= -100 million
If we use the definition of expected value we have this:

So then the expected value in the long run for this case would be 19 millions
1. thousands place value 3000
2. 3 hundred thousand value 300,000
Let us assume that x kg of 30% salt solution is mixed with (200-x) kg of 40% salt solution in order to obtain 200 kg of 37% salt solution.
We can set up a linear equation in terms of x by setting amount of total salt before mixing and after mixing equal to each other.

Therefore, 60 kg of 30% salt solution should be mixed with 140 kg of 40% solution.