A regular card deck contains 52 cards, 4 of which are aces. Assuming the cards are dealt randomly, what is the probability that the first card dealt will be an ace?
A regular card deck contains 52 cards, 4 of which are aces. Assuming the cards are dealt randomly, what is the probability that the first card dealt will be an ace?
A regular card deck contains 52 cards, 4 of which are aces. Assuming the cards are dealt randomly, what is the probability that the first card dealt will be an ace?
Answer:
1 cup of water will fill =
of the plastic container.
Step-by-step explanation:
Given :
of a cup of water fills
of a plastic container.
To find number of containers that can be filled with 1 cup of water, we will use unitary method.
if
of a cup of water fills
of a plastic container.
Then 1 cup of water will fill =
of a container.
Dividing fractions.

Replacing division with multiplication by taking reciprocal of the divisor.

Multiplying the numerators and denominators.


∴ 1 cup of water will fill =
of the plastic container.
U multiple 2 by those two 3x and 17
2(3x-17) = 6x-34
(5x + 3)(5x – 3)
(7x + 4)(7x + 4)
(x – 9)(x – 9)
(–3x – 6)(–3x + 6)
Answer:
- 1296 pounds per square inch
Step-by-step explanation:
<u>Direct variation equation:</u>
<u>In this case it is:</u>
- y = kx², where y- strength, x- depth of the beam, k- coefficient
<u>Substitute the given values and solve for k:</u>
- 3600 = k*10²
- 3600 = 100k
- k = 3600/100
- k = 36
<u>The equation becomes:</u>
<u>Now, find the value of y, when x is 6:</u>
<u><em>Note, I took the depth as 6 inches but the question is a bit confusing by saying "four six inches". If it is 4 inches then your answer will be:</em></u>