Answer:
See Explaination
Explanation:
public class testscope
{
//start of main function
public static void main(String[] args)
{
//varible declration
int i;
int x;
//loop for 10 times
for(i=0; i<10; i++)
{
//initialize value of x to 10
x = 10;
}
//the scope of variable x is visible outside of for loop
System.out.println("The value of x is: "+x);
}
}
See attachment for sample output
nb:
You can clearly see in the output of Java program the value of x is not printed and program return errors. It means the variable x declared inside for loop does not has scope outside the for loop.
Answer:
Redundancy
Req. 1 and Req. 3 are seemed to say the same thing. We need to remove the first sentence in Req. 1
Conflict and understandability
Req. 1 states that access is through web browser while Req. 4 states that access is via html. We have to re-write the Req. 3 to make it clear that users do not actually have to write directly html to communicate with the system.
Completeness
Req. 5 states that print out will “mainly” be documents. What else might be printed? What other inputs will be produced?
Either remove mainly or clarify other print out.
What version of html or web browser is assumed in Req. 1 and Req. 3?
Explanation:
Answer:
Mendix is another word for appendix.
Explanation:
Answer:
I would recommend the cloud because they can access their data on every single device. There are virtually no disadvantages to the cloud.
Explanation:
Hope this helps.
Answer:
static int checkSymbol(char ch)
{
switch (ch)
{
case '+':
case '-':
return 1;
case '*':
case '/':
return 2;
case '^':
return 3;
}
return -1;
}
static String convertInfixToPostfix(String expression)
{
String calculation = new String("");
Stack<Character> operands = new Stack<>();
Stack<Character> operators = new Stack<>();
for (int i = 0; i<expression.length(); ++i)
{
char c = expression.charAt(i);
if (Character.isLetterOrDigit(c))
operands.push(c);
else if (c == '(')
operators.push(c);
else if (c == ')')
{
while (!operators.isEmpty() && operators.peek() != '(')
operands.push(operators.pop());
if (!operators.isEmpty() && operators.peek() != '(')
return NULL;
else
operators.pop();
}
else
{
while (!operators.isEmpty() && checkSymbol(c) <= checkSymbol(operators.peek()))
operands.push(operators.pop());
operators.push(c);
}
}
while (!operators.isEmpty())
operands.push(operators.pop());
while (!operands.isEmpty())
calculation+=operands.pop();
calculation=calculation.reverse();
return calculation;
}
Explanation:
- Create the checkSymbol function to see what symbol is being passed to the stack.
- Create the convertInfixToPostfix function that keeps track of the operands and the operators stack.
- Use conditional statements to check whether the character being passed is a letter, digit, symbol or a bracket.
- While the operators is not empty, keep pushing the character to the operators stack.
- At last reverse and return the calculation which has all the results.
