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mote1985 [20]
3 years ago
6

Please help me figure this one out !!!

Mathematics
1 answer:
strojnjashka [21]3 years ago
5 0
These are "composite" functions.
g(x+a)  means insert (x+a) into g(x) to replace every x:
g(x+a) - g(x) = -5(x+a)^2 +4(x+a) +5x^2 - 4x
 = -5(x^2 + 2ax + a^2) +4x +4a + 5x^2 - 4x
Now just Multiply and sum up the answer.

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I will give branlest if your wright
Lelu [443]

Answer:

B

Step-by-step explanation:

Because all whole numbers are integers, but not all integers are whole numbers.

Hope this helps! :)

4 0
3 years ago
Read 2 more answers
London was offered a job that paid a salary of \$93,000$93,000 in its first year. The salary was set to increase by 2% per year
Tema [17]

Answer: Amount = $143776

Step-by-step explanation:

Given that London was offered a job that paid a salary of $93,000 in its first year. The salary was set to increase by 2% per year every year.

Let P = 93000

Rate R = 2%

The amount of salary he will receive after 22 years can be calculated by using exponential equation

A = P(1 + 2%)^t

Where t = 22 years

A = 93000(1.02)^22

A = 93000 × 1.545979

A = 143776.11 dollars

5 0
2 years ago
Read 2 more answers
What are the x-intercepts of the graphed function , (-3,0) and (0,1.5), (-3,0) and (1,0), (-1,2) and (1,0), (0,1.5) and (1,0)
serg [7]

Answer:

  (-3,0) and (1,0)

Step-by-step explanation:

x-intercepts are the points where the y-coordinate is zero. Based on the options you have listed, they are ...

  (-3,0) and (1,0)

_____

We'd need to see the graph to tell where it crosses the x-axis.

8 0
3 years ago
Name a diameter for the circle.<br> •DG<br> •EF<br> •DH<br> •FH
Sonbull [250]
It would be FH
A diameter is basically the length of the line through the centre that touches 2 points on a circles edges
4 0
3 years ago
What numbers would you multiply -3/4 by to equal 1?
Sonja [21]
You would multiply by -4/3. That's cuz to get to 1, you have to cancel out the negative, with another negative. You then have to multiply by the reciprocal. 

Hope this helps! 
7 0
3 years ago
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