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Nadusha1986 [10]
3 years ago
14

Find the common difference of the sequence shown 1/6, 1/4, 1/3

Mathematics
2 answers:
Anvisha [2.4K]3 years ago
8 0

Answer:

Common difference of the sequence is = \frac{1}{12}

Step-by-step explanation:

Common difference of any sequence is defined by the difference between a term and its successive term.

Sequence is \frac{1}{6}, \frac{1}{4},\frac{1}{3}.....

Common difference = T_{2}-T_{1}=\frac{1}{4}-\frac{1}{6}

                                 = \frac{2}{24}

                                 = \frac{1}{12}

Now we will do the same for T_{3} and T_{2}

T_{3}-T_{2} = \frac{1}{3}-\frac{1}{4}

= \frac{4-3}{12}

= \frac{1}{12}

Therefore, answer is \frac{1}{12}

Damm [24]3 years ago
7 0

1/4 - 1/6 = (6-4)/24 = 2/24 = 1/12
1/3 - 1/4 = (4-3)/12 = 1/12



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Solve. 2 (x - 1/2) = 3 (5 - 2x) show the steps in your solution.
viktelen [127]

Question 1.). Solve:

2 (x - 1 / 2) = 3 (5 - 2x)

Simplify both sides of equation:

2( x - 1 / 2 ) = 3(5 - 2x )

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Divide both sides by 8:

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Answer: 2 (x - 1 / 2) = 3 (5 - 2x) ==========> x = 2











Question 2.).

M =======> Amount Malik need

Solution: =========> m ≥ 5

Inequality ========> 8 + 7 + 10 + m ≥ 30

25 + m ≥ 30

Interpretation ==========> Malik needs at least, $5 .00 to get to, $30.00 or more.

Is the solution reasonable ===========> YES





Hope that helps!!!!! : )



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Answer:

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