Question

Find the common difference of the sequence shown 1/6, 1/4, 1/3

Answer 1

Answer:

Common difference of the sequence is = $\frac{1}{12}$

Step-by-step explanation:

Common difference of any sequence is defined by the difference between a term and its successive term.

Sequence is $\frac{1}{6}, \frac{1}{4},\frac{1}{3}.....$

Common difference = $T_{2}-T_{1}=\frac{1}{4}-\frac{1}{6}$

                                 = $\frac{2}{24}$

                                 = $\frac{1}{12}$

Now we will do the same for $T_{3}$ and $T_{2}$

$T_{3}-T_{2}$ = $\frac{1}{3}-\frac{1}{4}$

= $\frac{4-3}{12}$

= $\frac{1}{12}$

Therefore, answer is $\frac{1}{12}$

Answer 2

1/4 - 1/6 = (6-4)/24 = 2/24 = 1/12
1/3 - 1/4 = (4-3)/12 = 1/12