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Allushta [10]
2 years ago
8

Two teams of interns are wrapping donated gifts at a hospital. if the teams work alone, team a can wrap all of the gifts in 7 ho

urs, and team b can wrap all of the gifts in 5 hours. how many hours will it take the interns to wrap all of the gifts if both teams work together? round the answer to the nearest half hour.
Mathematics
1 answer:
romanna [79]2 years ago
4 0
Together it would take 3 hours.
Team A can wrap all gifts in 7 hours; thus they can wrap 1/7 of the gifts in 1 hour.

Team B can wrap all gifts in 5 hours; thus they can wrap 1/5 of the gifts in 1 hour.

1/7h + 1/5h = 1, where h is the number of hours; it equals 1 because it is 100% of the gifts;

Find a common denominator.  35 is the first thing 7 and 5 will both divide into.  Convert the fractions:
5/35h + 7/35h = 1
12/35h = 1

Divide both sides by 12/35:
12/35h ÷ 12/35 = 1 ÷ 12/35
h = 1/1 ÷ 12/35
h = 1/1 × 35/12
h = 35/12
h = 2.9
h ≈ 3
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Please solve this geometry equation with the work ! for 40 points and brainliest
topjm [15]

Answer:

D. 16 times.

Step-by-step explanation:

Volume of a cylinder = π r^2 h

π r^2 h = 432

Now if the diameter is reduced by 1/4 then the radius is reduced by a fourth also.

Let the new height be H, then:

432 = π (r/4)^2 H

so π r^2 h = π(r/4)^2 H

r^2 h = r^2 H / 16

h = H/16

H = 16h.

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2 years ago
Celine has a bottle that contains 20% of milk and the rest water. The bottle has 1 liter of water.
LUCKY_DIMON [66]
A] if .8=1 liter water, then .2=(1/4)(1)=.25 milk-->1.25liters in total
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3 years ago
Need help on this worksheet
andre [41]

Answer:

1. $1650

2. $1415.52

3. $5540

4. No

5. 145

6. No

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1. 2230 - 580

2. 157.28 x 9

3. 6630 - 1090

4.

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Hope this helps!

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2 years ago
F(x)=(x-2)2 <br> X=8<br><br><br><br><br><br> Need answers ASAP
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3 years ago
If tan A = 4/3 and sin B = 45/53 and angles A and B are in Quadrant I, find the value of tan(A+B)
lbvjy [14]

Answer:

First, find tan A and tan B.

cosA=35 --> sin2A=1−925=1625 --> cosA=±45

cosA=45 because A is in Quadrant I

tanA=sinAcosA=(45)(53)=43.

sinB=513 --> cos2B=1−25169=144169 --> sinB=±1213.

sinB=1213 because B is in Quadrant I

tanB=sinBcosB=(513)(1312)=512

Apply the trig identity:

tan(A−B)=tanA−tanB1−tanA.tanB

tanA−tanB=43−512=1112

(1−tanA.tanB)=1−2036=1636=49

tan(A−B)=(1112)(94)=3316

kamina op bolte

✌ ✌ ✌ ✌

3 0
2 years ago
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