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3 years ago

Complete each statement from the information given and state the reasons and the triangle criterion you used

Mathematics

1 answer:

kupik [55]3 years ago

8 0

Answer:

Triangle RED ≈ Triangle BUL

By-

SAS Congruencey

Beacause-

RE = BU (S)

ang RDE = ang BLU (A)

RD = BL (S)

(All the info for the relationship is given in the diagram itself)

Thus it's SAS Congruencey

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A taxi company charges $1.00 for the first mile (or part of a mile) and 20 cents for each succeeding tenth of a mile (or part).

meriva

Step-by-step explanation:

solving functions separately.

1st: from given data taxi charges $1.00 for the first mile.so it is first rule of function.

$y_{1} =1 , 0$

2nd: the company charge $0.20 per tenth of a mile.so 2nd rule of the function will be

$y_{2} =1+0.2.10(x-1)$

simplifying

$y_{2} =1+2(x-1)$

$y_{2} =x+2x-2$

$y_{2} =x$ , $1$

piece wise function is f(x)={2 , 0<x<1

{x , 1<x<2

the graph of the function is given below

7 0

3 years ago

Add 3/4+(−2 1/2) using the number line.

Neko [114]

Answer:

-1 3/4

Step-by-step explanation:

6 0

4 years ago

Determine whether the relation describe c as a function of w.

Delicious77 [7]

Answer:

Function:

c = f(w) = 0.49, 0 < w ≤ 1

= 0.70, 1 < w ≤ 2

= 0.91, 2 < w ≤ 3

Step-by-step explanation:

Yes, the relation described can be interpreted as a function.

Here, c is the cost of a mail letter. c depends upon w, which is the weights of the mail letter.

As described in the question, the relation can be expressed as a function.

c can be expressed as a function of w in the following manner:

c(cost of mail) = f(w), where w is the independent variable and c is the dependent variable

c = f(w) = 0.49, 0 < w ≤ 1

= 0.70, 1 < w ≤ 2

= 0.91, 2 < w ≤ 3

where, c is in dollars and w is in ounces.

5 0

4 years ago

Solve x^2+2x+7=0 using the quadratic formula.

Aneli [31]

Answer:

$x=-1\pm \sqrt{6}i$

Step-by-step explanation:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\frac{-(2)\pm\sqrt{2^2-4(1)(7)}}{2(1)}$

$x=\frac{-2\pm\sqrt{4-28}}{2}$

$x=\frac{-2\pm\sqrt{-24}}{2}$

$x=\frac{-2\pm\sqrt{-1*24}}{2}$

$x=\frac{-2\pm\sqrt{-1}\sqrt{24}}{2}$

$x=\frac{-2\pm i\sqrt{4*6}}{2}$

$x=\frac{-2\pm i\sqrt{4}\sqrt{6}}{2}$

$x=\frac{-2\pm2i\sqrt{6}}{2}$

$x=-1\pm \sqrt{6}i$

5 0

3 years ago

Name the postulate or theorem, 50 points please help!

max2010maxim [7]

Hi!

When you use postulates and theorems, you need to make sure to only use the given information that you know. Look for the given statements, and congruence marks on the figure. Those are also considered given.

By looking, you are given an angle and a side. The side comes first. SU=TV.

So, that makes it so Side-Angle-Side would be the best option.

I hope this helps!

7 0

3 years ago

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