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lukranit [14]
3 years ago
11

find the length of each isosceles right triangle when the hypotenuse of the given measure given 5 to the square root of 6

Mathematics
1 answer:
iragen [17]3 years ago
8 0

In isosceles right triangle, legs are equal. Let each leg is of x units . And the given hypotenuse is 5 square 6. We use pythagorean identity here, which is

a^2 + b^2 = c^2

Where a=b=x and c= 5 square root 6

x^2 +x^2 =(5 \sqrt6)^2

2x^2 = 150

x^2 =75

x= 5 \sqrt 3

And that's the length of both the legs . ANd that's the required answer .

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Write a formula for the general term or nth term for the sequence. Then find the indicated term. three fourths comma three sixte
Alexxandr [17]
Sequence: 3/4, 3/16, 3/64, 3/256
a8=?
a1=3/4
a2=3/16
a3=3/64
a4=3/256

a2/a1=(3/16)/(3/4)=(3/16)*(4/3)=4/16=1/4
a3/a2=(3/64)/(3/16)=(3/64)*(16/3)=16/64=1/4
a4/a3=(3/256)/(3/64)=(3/256)*(64/3)=64/256=1/4
a2/a1=a3/a2=a4/a3=r=1/4

an=a1*r^(n-1)
an=(3/4)*(1/4)^(n-1)
an=(3/4)*(1)^(n-1)/(4)^(n-1)
an=(3/4)*(1/4^(n-1))
an=(3*1)/[4*4^(n-1)]
an=3/4^(1+n-1)
an=3/4^n

n=8→a8=3/4^8
a8=3/65,536

Answers:
The general term or nth term for the sequence is: an=3/4^n
a8=3/65,536
3 0
3 years ago
What is the slope of the line that passes through points (-1,5) and (2,-3)
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Step-by-step explanation:

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A rectangular box is designed to have a square base and an open top. The volume is to be 500in.3 What is the minimum surface are
mr_godi [17]

The minimum surface area that such a box can have is 380 square

<h3>How to determine the minimum surface area such a box can have?</h3>

Represent the base length with x and the bwith h.

So, the volume is

V = x^2h

This gives

x^2h = 500

Make h the subject

h = 500/x^2

The surface area is

S = 2(x^2 + 2xh)

Expand

S = 2x^2 + 4xh

Substitute h = 500/x^2

S = 2x^2 + 4x * 500/x^2

Evaluate

S = 2x^2 + 2000/x

Differentiate

S' = 4x - 2000/x^2

Set the equation to 0

4x - 2000/x^2 = 0

Multiply through by x^2

4x^3 - 2000 = 0

This gives

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Divide by 4

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Take the cube root

x = 7.94

Substitute x = 7.94 in S = 2x^2 + 2000/x

S = 2 * 7.94^2 + 2000/7.94

Evaluate

S = 380

Hence, the minimum surface area that such a box can have is 380 square

Read more about surface area at

brainly.com/question/76387

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13(9x)

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Step-by-step explanation:

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3 years ago
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