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weeeeeb [17]
3 years ago
14

Find the equation of the line shown

Mathematics
2 answers:
love history [14]3 years ago
6 0
Linear equation y=x+6
drek231 [11]3 years ago
5 0
The equation for the line is y=x+6

You might be interested in
Please help thank you.
alina1380 [7]
Hello!

To solve this we use the equation sin60 = (s/2) / (d/2)

s is a side of the triangle
d is the diameter

sin60 = s/d

\sqrt{3/4} =s/d

d=s/ \sqrt{3/4}

d = s \sqrt{4/3}

d = 2s/ \sqrt{3}

put 6 in for s

d=12/ \sqrt{3}

d =  \sqrt{48}

d = 6.9

The answer is C) 6.9

Hope this helps!
5 0
3 years ago
Es of two children are 11 and 8 years.
nikdorinn [45]

Answer:

<em>In 5 years the product of their ages will be 208</em>

Step-by-step explanation:

The age of two children is 11 and 8 years.

Let's call x the number of years ahead.

We need to find when the product of their future ages is 208. The 11 years old child will be 11+x years old and the other child will be 8+x years, thus:

(11+x)(8+x)=208

Operating:

88+11x+8x+x^2=208

Simplifying:

x^2+19x-120=0

Factoring:

(x-5)(x+24)=0

Solving:

x=5, x=-24

The negative solution is not valid, thus x=5

In 5 years the product of their ages will be 208

3 0
2 years ago
Para encher 2/5 de uma piscina são necessários 60.000 litros de água. Qual é a capacidade dessa piscina?
natali 33 [55]

Answer:

A capacidade dessa piscina é de 150.000 litros de água.

Step-by-step explanation:

A capacidade da piscina é de x.

Para encher 2/5 de uma piscina são necessários 60.000 litros de água.

Isto implica que:

\frac{2x}{5} = 60000

2x = 60000*5

x = \frac{60000*5}{2}

x = 150000

A capacidade dessa piscina é de 150.000 litros de água.

8 0
2 years ago
Find the value of c .<br> 5/2 = c/22<br> c = ___.
sleet_krkn [62]

Answer:

c = 55

Step-by-step explanation:

8 0
3 years ago
Consider the following hypothesis test H0 p 20 Ha p 20 A sample of 400 provided a sample proportion p 175 a Compute the value of
Bogdan [553]

Answer:

a) -1.25

b) 0.2112

c) -1.96

Step-by-step explanation:

Data provided in the question:

Sample size, n = 400

H0 : p = 20

\bar{p} = 175

Now,

a) The test statistic is  given as:

Z = \frac{(\bar{p}-p)}{\sqrt{\frac{p(1-p)}{n}}}

on substituting the respective values, we get

Z = \frac{(0.175-0.2)}{\sqrt{\frac{0.2\times0.8}{400}}}

= -1.25

b) The p-value = 2 × P(Z <-1.25)

Now from the standard normal table

P(Z <-1.25) = 10.56% = 0.1056

Thus,

p-value = 2 × 1056 = 0.2112

c) for a = 0.05,

the critical value is Z_{\frac{a}{2}}=Z_{\frac{0.05}{2}} i.e Z_{0.025}

Now from standard normal table

Z_{0.025} = -1.96

3 0
3 years ago
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