Answer:
Part A)
6 m/s²
Part B)
-3 m/s.
Step-by-step explanation:
We are given that the velocity, in meters per second, of an object at a time <em>t </em>for <em>t</em> ≥ 0 is given by the function:
Part A)
To find the average acceleration of the object during the first two seconds, we can find the average slope of <em>v</em> from <em>t</em> = 0 to <em>t</em> = 2. Hence:
Hence, the average acceleration of the object during the first two seconds was 6 m/s².
Part B)
Recall that acceleration is the derivative of the velocity function. In other words:
Substitute and solve:
To find the time(s) for which the acceleration is equal to 4, set <em>a</em> equal to 4 and solve for <em>t: </em>
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Since <em>t</em> ≥ 0, we can ignore the second solution.
Evaluate <em>v</em> at <em>t</em> = 1:
In conclusion, when the acceleration is 4 m/s² at <em>t</em> = 1, the velocity is -3 m/s.
Answer:
Zero
Step-by-step explanation:
Find the slope using rise over run (y2 - y1) / (x2 - x1)
Plug in the points:
(y2 - y1) / (x2 - x1)
(4 - 4) / (4 - 0)
0 / 4
= 0
So, the slope is zero.
Answer:
93912/391
Step-by-step explanation:
Answer:
A) (x + 2)
Step-by-step explanation:
x^2 + 5x + 6
=(x +3)(x +2)
so (x+3) and (x+2) are the factors