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En Colima se lleva acabo la conferencia sobre la energética eólica a la cual asistieron 120 representantes de Latinoamérica y Su

andriy [413]

The first thing we must do for this case is to see how many representatives from each country attended.
We have then:
Argentines = (1/6) * (120) = 20
Chileans = (1/5) * (120) = 24
Bolivians = (1/4) * (120) = 30
Venezuelans = (1/4) * (120) = 30
Adding we have:
20 + 24 + 30 + 30 = 104
Therefore the number of Americans is:
120-104 = 16
Answer:
16 Americans attended the wind energy conference

4 0

3 years ago

What cell generates energy for all the other cells (it’s for science but it doesn’t show science as a subject so yes)

Harlamova29_29 [7]

lol, that would be biology

but I'd say its the mitochondria

5 0

2 years ago

Which equation could be solved using this application of the quadratic formula? A. -2x2 â’ 8 = 10x â’ 3 B. 3x2 â’ 8x â’ 10 = 4 C

hodyreva [135]

The given question can be solve using quadratic formula.

The correct option is (c) $3x^2 +8x -10=-8$ .

Given:

The given equation is,

$x=\dfrac{-8\pm\sqrt{8^2-4(3)(-1)}} {2(3)}$ ---------------------------(1)

Write the general quadratic equation.

$ax^2 + bx +c=0$

Write the quadratic formula.

$x =\dfrac {-b \pm \sqrt{(b^2 - 4ac)} } {2a}$ ------------------------------- (2)

Compare equation (1) and (2).

$a=3\\b=8\\c=-2$

Substitute the value of $a$ , $b$ and $c$ in general quadratic.

$3x^2 +8x -2=0$

Subtract $8$ from each side of above equation.

$3x^2 +8x -2 -8=0-8\\3x^2 +8x -10=-8$

Thus, the correct option is (c) $3x^2 +8x -10=-8$ .

Learn more about quadratic equation here:

brainly.com/question/17177510

6 0

2 years ago

In a survey, 11 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped

pickupchik [31]

Answer:

The population standard deviation is not known.

90% Confidence interval by T₁₀-distribution: (38.3, 53.7).

Step-by-step explanation:

The "standard deviation" of $14 comes from a survey. In other words, the true population standard deviation is not known, and the $14 here is an estimate. Thus, find the confidence interval with the Student t-distribution. The sample size is 11. The degree of freedom is thus $11 - 1 = 10$ .

Start by finding 1/2 the width of this confidence interval. The confidence level of this interval is 90%. In other words, the area under the bell curve within this interval is 0.90. However, this curve is symmetric. As a result,

The area to the left of the lower end of the interval shall be $1/2 \cdot (1 - 0.90)= 0.05$ .
The area to the left of the upper end of the interval shall be $0.05 + 0.90 = 0.95$ .