No solution
Because 3 unknown needs 3 equation at least
Answer:
10
Step-by-step explanation:
Firstly, AM=x+8
or, A=x+8-M......eqn (i)
MB=6x-2
or, B=6x-2-M......eqn (ii)
Now,
from eqn (i) and (ii)
x+8-M=6x-2-M
or, 8+2=6x-x-M+M
or, 10=5x
or, 10÷5=x
therefore, x=2
Again,
MB=6x-2
=6×2-2
=12-2
=10
is it correct
please mark me as BRAINLIEST
Five consecutive integers are:
n, n+1, n+2, n+3, n+4 the sum of which is:
5n+10=265 subtract 10 from both sides
5n=255, divide both sides by 5
n=51
Our fifth number was n+4 so the fifth number is 55
Step-by-step explanation:
f(x)=2x-7.
by substituting value 0 for x,
f (0)=2×0-7
f (0)=-7
